Solve 3x+2y=7 and x-4y=-21 by using substitution
1 answer:
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The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100
200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>Thus the cost of children’s ticket is $ 5
Answer:
On dividing, we found that the quotient is (x-4) and the remainder is equal to 0.
Step-by-step explanation:
We need to find the quotient and the remainder for the following (x²-10x+24)÷(x+6).
The numerator is (x²-10x+24) and the denominator is (x+6). It can be written as :
On dividing, we found that the quotient is (x-4) and the remainder is equal to 0.