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just olya [345]
3 years ago
6

Solve 3x+2y=7 and x-4y=-21 by using substitution

Mathematics
1 answer:
noname [10]3 years ago
7 0
3x+2y=7 \\
x-4y=-21 \\ \\
\hbox{solve the second equation for x:} \\
x-4y=-21 \\
x=4y-21 \\ \\
\hbox{substitute 4y-21 for x in the first equation:} \\
3(4y-21)+2y=7 \\
12y-63+2y=7 \\
14y=7+63 \\
14y=70 \\
y=\frac{70}{14} \\
y=5 \\ \\
x=4y-21=4 \times 5-21=20-21=-1 \\ \\
\boxed{(x,y)=(-1,5)}
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#2 and please provide explaination !
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Answer:

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Step-by-step explanation:

<em>Step 1: Assume the value of oranges</em>

Let oranges be x

Oranges = x

Apples = 32 + x

Overripe oranges = 3/5 of oranges

                              = 3x/5

Overripe apples = 1/3 of apples

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<em>Step 2: Find x (oranges)</em>

<em>Number of overripe apples and number or overripe oranges are equal.</em>

3x/5 = 1/3 (32 + x)

3 (3x) = 5(32 + x)

9x = 160 + 5x

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<em>Step 3: Find the total number of overripe fruit.</em>

Total overripe fruit = Overripe apples + Overripe oranges

Total overripe fruit = 1/3 (32 + x) + 3x/5

Total overripe fruit = 1/3 (32 + 40) + 3(40)/5

Total overripe fruit = 24 + 24

Total overripe fruit = 48

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