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vovangra [49]
3 years ago
12

The standard form 0. 00293768 is

Mathematics
2 answers:
aleksandrvk [35]3 years ago
6 0

Answer:

0.00293768 \\  \frac{293768}{100000000}  \\ 2.93768 \times  {10}^{ - 3}

disa [49]3 years ago
3 0
The standard form is:
2.93768 x 10^-3
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Permutations are written as nPx where n is the number of total choices possible and x is the number of choices that will be used. This is calculated as nPx = n! / (n-x)!.
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If an item is $6.49 for 36 ounces, then it is $
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Situation:
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Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

<u>Given formula:</u>

\sf N=N_0e^{-kt}

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  • N = mass (at time t)
  • k = a positive constant
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Half-life:  The <u>time</u> required for a quantity to reduce to <u>half of its initial value</u>.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

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2 years ago
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The midpoint of PQ is (–6, –3). One endpoint of PQ is P(–1, –4). What are the coordinates of Q? A. Q(–11, –2) B. Q(–3.5, –3.5) C
skelet666 [1.2K]
The coordinates of the midpoint of the line segment is the average of the coordinates of both end points. For this example above, let (x, y) be the coordinates of point Q. 

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