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Radda [10]
3 years ago
9

Find the hypotenuse

Mathematics
2 answers:
Anika [276]3 years ago
8 0
A^2+b^2=c^2
11^2+4^2=c^2
121+16=c^2
137=c^2
\sqrt{137}  =  \sqrt{c}
11.70=c

lakkis [162]3 years ago
8 0

Answer:

Hypotenuse = 11.70 :)

Step-by-step explanation:

Let's use the pythagorean theorem, which is a^2 + b^2=c^2

C^2 is always going to be the hypotenuse, so the rest of the order doesn't really matter. 11^2 is 121 and 4^2 is 16, added together it's 137. Then you just need to find the square root of that, it's 11.7046999107. Just round it to the nearest hundreth, which is 11.70.

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Prove that 25^11−5^19 is divisible by 31.
SCORPION-xisa [38]

Answer:

Divisible by 3 is the answer

Step-by-step explanation:

First get everything to have the same base of 5

25^11 - 5^19

(5^2)^11 - 5^19

5^(2*11) - 5^19

5^22 - 5^19

Now factor out the GCF 5^19 to get

5^22 - 5^19

5^(19+3) - 5^(19+0)

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At this point, we factor the 124 into 31*4 to end up with this full factorization: 5^19*31*4

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4 0
3 years ago
Ari lives 4/5 of a mile from the park she has already walked 3/4 of the way to the park. How far has ari walked
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Answer:

Step-by-step explanation:

The only graph shown in the question doesn't have amplitude 1/2. look for a graph of a periodic wave function that has maximum y-value 1/2 (0.5) and minimum y-value 1/2 (0.5), or if it is not oscillating around the x-axis, verifies that the distance between minimum y-value and maximum y-value is "1" (one). This is because the amplitude is half of the peak-to-peak distance.

Look at the attached image as example.

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