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2 years ago

The mass of the electron is

Mathematics

1 answer:

sweet [91]2 years ago

4 0

Very small compared to the proton

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18 + x = 10 x=____ help

hodyreva [135]

Answer:

X=-8

Step-by-step explanation:

18+x=10

-18 -18

x=-8

7 0

2 years ago

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A cube has a volume of 216 cubic inches. What is the width of the cube?

Anarel [89]

Answer:

Step-by-step explanation:

Find the cube root of 216

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2 years ago

Which type of graph is typically not used for quantitative data?

Verdich [7]

Answer:

A histogram often looks similar to a bar graph, but they are different because of the level of measurement of the data. Bar graphs measure the frequency of categorical data. A categorical variable is one that has two or more categories, such as gender or hair color

Step-by-step explanation:

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3 years ago

If sin theta= - 5/7, which of the following are possible?

Sphinxa [80]

Answer:

$\large\boxed{\sec\theta=\dfrac{7}{\sqrt{24}},\ and\ \tan\theta=-\dfrac{5}{\sqrt{24}}}\\\boxed{\cos\theta=\dfrac{\sqrt{24}}{7},\ and\ \tan\theta=\dfrac{5}{\sqrt{24}}}$

Step-by-step explanation:

$\text{Use:}\\\\\sin^2\theta+\cos^2\theta=1\to\cos\theta=\pm\sqrt{1-\sin^2\theta}\\\\\tan\theta=\dfrac{\sin\theta}{\cos\theta}\\\\\sec\theta=\dfrac{1}{\cos\theta}\\\\==========================\\\\\sin\theta=-\dfrac{5}{7}\\\\\cos\theta=\pm\sqrt{1-\left(-\frac{5}{7}\right)^2}=\pm\sqrt{1-\frac{25}{49}}=\pm\sqrt{\frac{24}{49}}=\pm\dfrac{\sqrt{24}}{\sqrt{49}}=\pm\dfrac{\sqrt{24}}{7}\\\\\sec\theta=\pm\dfrac{1}{\frac{\sqrt{24}}{7}}=\pm\dfrac{7}{\sqrt{24}}$

$\tan\theta=\pm\dfrac{-\frac{5}{7}}{\frac{\sqrt{24}}{7}}=\mp\dfrac{5}{7\!\!\!\!\diagup_1}\cdot\dfrac{7\!\!\!\!\diagup^1}{\sqrt{24}}=\mp\dfrac{5}{\sqrt{24}}$

$\sin\theta=-\dfrac{5}{7}$

6 0

2 years ago

Which explanation correctly solves this problem?

Molodets [167]

Hello!

The Correct Answer for this Question would be:

"<span>Start with 10.5. Add 3.5 and 10.5. Add 2.25 to the sum. Then add 5 to the answer."

In Other Words, Option "B".

Hope this Helps! Have A Wonderful Day! :)</span>

8 0

3 years ago

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