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3 years ago

8

What is the graph of y = cos(x) +3?

2 answers:

jek_recluse [69]3 years ago

5 0

Graph y=cos(x)+3. y=cos(x)+3. Use the form acos(bx−c)+d a c o s ( b x - c ) + d to find the variables used to find the amplitude, period, phase shift, and vertical shift. a=1.

dimaraw [331]3 years ago

4 0

Answer:

Given function: f(x) = cos x + 3

To Draw: Graph of f(x)

As we know graph of trigonometric function cos x is a continuous graph with amplitude 1 .i.e., graph is 1 unit above and 1 unit down from the middle of graph.

If we add a constant to the trigonometric function it does not change any thing it just shift the function up or down according to value of constant.

Here 3 is added to cos x ⇒ Gr pah of cos x will be shifted 3 units upward.

Therefore, The graph we obtain is attached.

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What is an equivalent expression for x=3y-2

ioda

X = 3(y - 2/3) ...distribute thru the parenthesis
x = 3y - 6/3...reduce
x = 3y - 2

so ur answer is : x = 3(y - 2/3)

5 0

3 years ago

lys-0071 [83]

Answer:

361/900

Step-by-step explanation:

$\left(-\dfrac{1}{6}+0.6\left(-\dfrac{1}{3}\right)+1\right)^2=\left(-\dfrac{1}{6}-0.2+1\right)^2\\\\=\left(1-\left(\dfrac{1}{6}+\dfrac{1}{5}\right)\right)^2=\left(1-\dfrac{5+6}{6\cdot5}\right)^2=\left(\dfrac{19}{30}\right)^2=\boxed{\dfrac{361}{900}}$

8 0

2 years ago

Help plzzz thank you !

VashaNatasha [74]

Answer:

a. Ameribank-$15,157.50

b. Capital Two-$4,646.25

Step-by-step explanation:

a. Tad's savings is $15,000, we calculate his total amount at the end of the year for each bank:

#Ameribank

$A=P+I=P+PRT\\\\=15000+15000\times 0.0105\times 1\\\\=\$15,157.50$

#Huffington( we use the effective rate to calculate the compound amount):

$i_m=(1+i/m)^m-1\\\\=(1+0.0095/12)^[12}-1=0.009541\\\\A=P(1+i_m)^n\\\\=15000(1.009541)^1\\\\=\$15,143.12$

#Sixth-Third, Take 1 yrs=52 weeks:

$i_m=(1+i/m)^m-1\\\\=(1+0.01/52)^{52}-1=0.01005\\\\A=15000(1.01005)^1\\\\=\$15,150.74$

#Hence, Ameribank is the best option as his money grows to $15,157.50 which is greater than all the remaining two options.

b. We use the compound interest formula $A=P(1+r/n)^{nt}$ to determine which bank gives the best option:

#Capital Two. r=3.75%, n=12,t=4

$A=P(1+r/n)^{nt}\\\\=4000(1+0.0375/12)^{12\times4}\\\\=\$4,646.25$

#J.C Morgan, t=2, r=3.55% n=12

$A=P(1+r/n)^{nt}\\\\=4000(1+0.0355/12)^{12\times 2}\\\\=\$4,293.87$

#Silverman Slacks, n=12,t=3, r=3.65%

$A=P(1+r/n)^{nt}\\\\=4000(1+0.0365/12)^{12\times3}\\\\=\$4,462.14$

We compare the investment amounts after t years:

$Capital>Silver>Morgan=4646.25>4462.14>4293.87$

Hence, Capital two is the best option with an investment amount of $4,646.25

8 0

3 years ago

Read 2 more answers

HELP WILL GIVE BRAINLIEST

AnnyKZ [126]

<h2>Good evening ,</h2>

<em><u>Answer</u></em>:

q=-10

<em><u>Step-by-step explanation:</u></em>

D:y=-3x+q

let’s find q

A(-4,2)∈D ⇔ 2=-3(-4)+q ⇔ q=-10

then D:y=-3x-10

look at the photo for more details.

______________

:)

5 0

2 years ago

Which statement is correct about relations and functions?

artcher [175]

It is number 3 I am pretty sure if it’s wrong I’m sorry but I got it right on mine

3 0

3 years ago