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A number has only 1 factor pair. One of its factors is twice the other factor. What is the number? Explain.

Mrrafil [7]

<h3>Answer: 2</h3>

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Explanation:

If a number only has one factor pair, then that number must be prime. This is because prime numbers only have factors of 1 and the number itself.

For instance, the value 7 is prime because the only factors of this are 1 and 7.

For something like the number 32, it is composite and not prime because it has the factors {1,2,4,8,16,32} and it leads to these three factor pairs: 1*32, 2*16, 4*8. This is one example showing why the answer isn't composite.

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Let's say that p is the unknown prime we want to find. The factors of this are 1 and p. We're told that "one of the factors is twice the other factor", so that must mean p = 2*1 = 2. We can see that 2 is twice that of 1.

8 0

3 years ago

Find the measure of KL

SVETLANKA909090 [29]

Answer:

4.2

Step-by-step explanation:

Because RM and ML are the same, that makes KL and KR congruent. Hope his helps. :)

8 0

3 years ago

Read 2 more answers

Find a quadratic expression with integer coefficients whose roots are <img src="https://tex.z-dn.net/?f=5%2F2%2B%203i" id="TexFo

prohojiy [21]

Answer:

4x² -20x +61

Step-by-step explanation:

the quadratic equation can be written as (x-root1)(x-root2)

(x-(5/2) -3i) (x-(5/2)+3i), distribute

x² -(5/2)x +3xi -(5/2)x + 25/4 -(15/2)i -3xi +(15/2)i -9i², simplify

x² -(5/2)x -(5/2)x + 25/4 -9i², use the fact that i² =(√-1)² = -1 and substitute i²

x² -(5/2)x -(5/2)x + 25/4 +9, combine like terms and rewrite 9 as 36/4

x² -(10/2)x +25/4 + 36/4, combine like terms and simplify

x² -5x +61/4 is the quadratic expression yet it does not have integer coefficients so multiply by 4 to have all coefficients integers

4x² -20x +61

7 0

3 years ago

What does 1.6666 equal

lana66690 [7]

8333/5000 have a brainly day :)

8 0

3 years ago

Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4

dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

$x_1\ =\ -2$

$y_1\ =\ 3$

$z_1\ =\ -4$

Distance is measure across the line

$\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}$

So, we can write

$\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k$

$=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k$

$=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k$

$=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}$

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

$3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3$

$=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18$

$=>18k-24+12k+9+10k-32\ =\ 18$

$=>\ k\ =\dfrac{13}{8}$

So,

$x\ =\ 3k-4$

$=\ 3\times \dfrac{13}{8}-4$

$=\ \dfrac{7}{4}$

$y\ =\ \dfrac{4k+3}{2}$

$=\ \dfrac{4\times \dfrac{13}{8}+3}{2}$

$=\ \dfrac{19}{4}$

$z\ =\ \dfrac{5k-16}{3}$

$=\ \dfrac{5\times \dfrac{13}{8}-16}{3}$

$=\ \dfrac{-21}{8}$

Now, the distance of point from the plane is given by,

$d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}$

$=\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}$

$=\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}$

$=\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}$

$=\ \sqrt{\dfrac{1177}{64}}$

$=\ 4.28$

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

= 8.56 unit

So, the distance of a point from it's image is 8.56 units.

4 0

3 years ago