Find the equation of the tangent line to the curve y=6sinx at the point (π/6,3

1 answer:

6 0

Hello:
f(x) =6sin(x)
f'(x) = 6 cos(x)

the equation of the tangent line is : y=f'(π/6)(x-π/6)+f(<span>π/6)
f'(</span>π/6)=6cos(π/6)=6×(√3/2)=3<span>√3
f(</span>π/6) =3
the equation is : y = 3√3(x-π/6)+3

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