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Marizza181 [45]
4 years ago
5

Find the equation of the tangent line to the curve y=6sinx at the point (π/6,3

Mathematics
1 answer:
Aloiza [94]4 years ago
6 0
Hello:
f(x) =6sin(x)
f'(x) = 6 cos(x)

the equation of the tangent line is : y=f'(π/6)(x-π/6)+f(<span>π/6)
f'(</span>π/6)=6cos(π/6)=6×(√3/2)=3<span>√3
f(</span>π/6) =3
the equation is :  y = 3√3(x-π/6)+3
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navik [9.2K]

Answer:

x=-6

Step-by-step explanation:

(\frac{2^{7}}{2^{9}})^{3} \\(\frac{128}{512})^{3} \\(\frac{1}{4})^{3}\\(\frac{1}{4})*(\frac{1}{4})*(\frac{1}{4})\\\frac{1*1*1}{4*4*4} \\\frac{1^{3} }{4^{3} } \\\frac{1}{64} \\2^{x}=\frac{1}{64}\\log 2^x=log\frac{1}{64}\\x*(log(2))=log\frac{1}{64}\\x=\frac{log\frac{1}{64}}{log(2)} \\x=-6

4 0
3 years ago
I will give brainiest to whoever answers correctly !!
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3 years ago
Jayden has been reading a 275275275-page book for english class. on average, he has read about 101010 pages in 151515 minutes (\
Vitek1552 [10]
<span>75 pages.
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   To make things easier, first convert the time to just minutes. So 5 * 60 + 50 = 300 + 50 = 350 minutes.

   Now let's use the variable X for the number of minutes spent skimming and (350-X) for the number of minutes spent reading.
 X * 15/10 + (350 - X)*10/15 = 275

   Solve for X.
 X * 15/10 + (350 - X)*10/15 = 275
 X * 15/10 + 350*10/15 - X*10/15 = 275
 X * 15/10 - X*10/15 = 275 - 350*10/15
X(15/10 - 10/15) = 275 - 3500/15
 X(45/30 - 20/30) = 825/3 - 700/3
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7 0
3 years ago
Quick first one gets brainliest
Free_Kalibri [48]

c is there answer                                                                                                  Step-by-step explanation: 4 is greater than 3  and because the  aligator eats the biggest number lol

5 0
3 years ago
This trapezium is drawn on a centimetre grid.<br> Find the area of the trapezium.
aivan3 [116]

Answer:

20 unit²

Step-by-step explanation:

A trapezium is given to us on the grid and we need to find out the area of the trapezium . In order to find the area , we need to find the measure of the parallel sides and the distance between the parallel sides.

<u>From </u><u>the</u><u> </u><u>grid</u><u> </u><u>:</u><u>-</u>

\rm\implies Side_1 = 7 \ units

\rm\implies Side_2 = 3 \ units

\rm\implies \perp \ Distance =4  \ units

Now here we got the two parallel sides of the trapezium and the distance between the two parallel sides. Now we can find the area as ,

\rm\implies Area_{Trapezium}= \dfrac{1}{2}\times ( s_1 + s_2) \times   \perp \ Distance \\\\\rm\implies Area = \dfrac{1}{2} \times ( 7 + 3 ) \times 4 \ unit^2 \\\\\rm\implies Area = \dfrac{1}{2} \times ( 10) \times 4 \ unit^2 \\\\\rm\implies\boxed{\rm  Area = 20 \ unit^2}

3 0
3 years ago
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