Let
x = larger integer
y = smaller integer
The two integers (x and y) have a sum of 42 which means they add to 42
x+y = 42
solve for y to get
y = 42-x
simply by subtracting x from both sides
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The two integers have a difference of 22. This translates to "subtract the values and the result will be 22", i.e.,
x-y = 22
Plug in y = 42-x. Solve for x
x-y = 22
x-(y) = 22
x - (42-x) = 22
x - 42 + x = 22
2x - 42 = 22
2x - 42+42 = 22+42
2x = 64
2x/2 = 64/2
x = 32
If x = 32, then y is...
y = 42-x
y = 42-32
y = 10
Therefore,
x = 32
y = 10
The final answer is 10
Answer:
2.83 units
(results are in decimal form, rounded to the nearest 100th)
Answer:
I think 80
Step-by-step explanation:
100/15=6.66666667
12x6.67=80.4
Answer:
3( 3+5)
Step-by-step explanation:
9 +15
Rewriting 9 as 3*3 and 15 * 3*5
3*3 + 3*5
Factor out 3
3( 3+5)
Answer:
no 146.5 > 145
Step-by-step explanation:
