Answer:
0.84 square in
Step-by-step explanation:
Since the capacity of the cable is proportional to its cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold
2500 / 0.3 = 8333.33 lb/in
To old 7000 lb it the cross-sectional area would need to be
7000 / 8333.33 = 0.84 square in
Step-by-step explanation:
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Answer is 0.7 degrees celcius per minute
Explanation:
given that T(t) = 42-0.7t
We have to find the rate of drop of temperature.
For that we find drop of T in 1 minute
Consider T(t) for t minutes and t+1 minutes
T(t+1) = 42-0.7(t+1)
T(t) = 42-0.7t
Difference i.e. drop in temperature in one minute
= T(t+1)-T(t)
= 42-0.7(t+1)-(42-0.7t) =-0.7
Hence drop per minute = 0.7 degree celcius.
