Ask question

Ask question

All categories

2 years ago

14

You are doing a measurement to determine the conductance of an artificial membrane. The membrane is selectively permeable to Na

. The temperature is 15 degrees C The external concentrate of Na is 500 mM The internal concentration of Na is 70 mM Using a voltage clamp apparatus you clamp the membrane voltage (Vm) at 20 mV At this clamped voltage you measure a current of -71 nA What is the membrane's conductance

1 answer:

alex41 [277]2 years ago

8 0

Answer:

What is the membrane's conductance = 2.47miuS

Explanation:

The detailed step and appropriate formula is as shown in the attached file.

You might be interested in

Two identical closely spaced circular disks form a parallel-plate capacitor. Transferring 1.4×109 electrons from one disk to the

allsm [11]

Answer:

r = 6.5*10^-3 m

Explanation:

I'm assuming you meant to ask the diameters of the disk, if so, here's it

Given

Quantity of charge on electron, Q = 1.4*10^9

Electric field strength, e = 1.9*10^5

q = Q * 1.6*10^-19

q = 2.24*10^-10

E = q/ε(0)A, making A the subject of formula, we have

A = q / [E * ε(0)], where

ε(0) = 8.85*10^-12

A = 2.24*10^-10 / (1.9*10^5 * 8.85*10^-12)

A = 2.24*10^-10 / 1.6815*10^-6

A = 1.33*10^-4 m²

Remember A = πr²

1.33*10^-4 = 3.142 * r²

r² = 1.33*10^-4 / 3.142

r² = 4.23*10^-5

r = 6.5*10^-3 m

3 0

2 years ago

What is the definition of major plates?

lutik1710 [3]

Answer:

The outer shell of the earth, the lithosphere

Explanation:

The seven major plates are the African plate, Antarctic plate, Eurasian plate, Indo-Australian plate, North American plate, Pacific plate and South American plate.

7 0

2 years ago

When recyclable materials are sent to a recycling plant, they are often not sorted in any particular way. Plastic materials migh

4vir4ik [10]

Answer:

by applying a magnetic force to recycled materials

8 0

3 years ago

Read 2 more answers

2. One mole of a monatomic ideal gas undergoes a reversible expansion at constant pressure, during which the entropy of the gas

Anna35 [415]

Answer:

The initial and final temperatures of the gas is 300 K and 600 K.

Explanation:

Given that,

Entropy of the gas = 14.41 J/K

Absorb gas = 6236 J

We know that,

$ds=\dfrac{dQ}{dt}$

At constant pressure,

$dQ=C_{p}dt$

$\Delta s=\int_{T_{1}}^{T_{2}}{\dfrac{C_{p}dT}{T}}$

$\Delta s=C_{p}ln\dfrac{T_{2}}{T_{1}}$

Put the value into the formula

$14.41=2.5\times8.3144(ln\dfrac{T_{2}}{T_{1}})$

$\dfrac{14.41}{2.5\times8.3144}=ln\dfrac{T_{2}}{T_{1}}$

$0.693=ln\dfrac{T_{2}}{T_{1}}$

$ln2=ln\dfrac{T_{2}}{T_{1}}$

$T_{2}=2T_{1}$ ...(I)

We need to calculate the initial and final temperatures of the gas

Using formula of energy

$\Delta Q=C_{p}\Delta T$

Put the value into the formula

$6236=2.5\times8.3144(T_{2}-T_{1})$

$6236=20.786(T_{2}-T_{1})$

$T_{2}-T_{1}=\dfrac{6236}{20.786}$

$T_{2}-T_{1}=300$

Put the value of T₂

$2T_{1}-T_{1}=300$

$T_{1}=300\ K$

Put the value of T₁ in equation (I)

$T_{2}=2\times300$

$T_{2}=600\ K$

Hence, The initial and final temperatures of the gas is 300 K and 600 K.

8 0

2 years ago

1. Two spherical objects have masses of 300 kg and 140 kg. Their centers are separated by a

SCORPION-xisa [38]

The concept that must be used to solve this problem is linked to Newton's laws of gravitation. Newton defined the gravitational attraction force as the product between the universal constant of gravitation, by the masses of each object, all this because of the change in the squared distance that separates them, mathematically it can be expressed as,

$F_G = \frac{G m_1 m_2}{r^2}$

Here,

G = Gravitational Universal Constant

$m_{1,2}$ = Mass of each object

r = Radius

Our values are,

$G = 6.67*10^{-11}N\cdot m^2/kg^2$

$m_1 = 300kg$

$m_2 = 140kg$

$r = 1.7m$

Replacing,

$F_G = \frac{(6.67*10^{-11}N\cdot m^2/kg^2 )(300kg)(140kg )}{(1.7m)^2}$

$F_G = 9.7*10^{-7} N$

8 0

3 years ago