Answer:
187.38 m
Explanation:
Using the equation of motion
s = ut + 1/2gt²...................... Equation 1
Where s = distance of fall, u = initial velocity of the rock, t = time taken for the rock to fall from rest, g = acceleration due to gravity of venus.
Given: u = 0 m/s ( from rest), t = 6.5 s, g = 8.87 m/s².
substituting into equation 1
s = 0(6.5) + 1/2(8.87)(6.5)²
s = 0 + 374.7575/2
s = 187.38 m.
Hence the rock will fall 187.38 m
Answer:
F = 196 N
Explanation:
For this exercise we will use Newton's second law, we define a reference system with the x axis in the direction of movement of the stones and the y axis vertically
Y axis
N- W = 0
N = mg
X axis
F -fr = ma
In this case, they ask us for the force to keep moving, so the stones go at constant speed, which implies that the acceleration is zero.
F- fr = 0
F = fr
the friction force has the equation
fr = μ N
fr = μ mg
we substitute
F = μ mg
let's calculate
F = 0.80 9.8 25
F = 196 N
Answer:
32s
Explanation:
We must establish that by the time the police car catches up to the speeder, both have travelled a certain distance during the same amount of time. However, the police car experiences accelerated motion whereas the speeder travels at a constant velocity. Therefore we will establish two formulas for distance starting with the speeder's distance:

and the police car distance:

Since they both travel the same distance x, we can equal both formulas and solve for t:

Two solutions exist to the equation; the first one being 
The second solution will be:

This result allows us to confirm that the police car will take 32s to catch up to the speeder