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NARA [144]
3 years ago
5

SAT verbal scores are normally

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

The percentage of the scores lying between 450 and 750 is 49.4%

Step-by-step explanation:

In this question, we are simply asked to calculate the percentage of the scores lying between a particular range.

The first thing to do here is to calculate the z score of both scores

Mathematically, z score = (x - mean)/SD

for score 450, we have ; z = (450-450)/120 = 0/120 = 0

For score 750, we have z = (750-450)/120 =

2.5

Now, we move on to calculate the probability before turning it into a percentage.

The supposed probability we are to calculate is as follows;

P(450 < x < 750) or P(0 < z < 2.5)

Using standard score table, P = 0.49379

The percentage is thus 49.4%

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I provided the answers I just need you to show work. I’ll even mark you the Brainliest!
Sindrei [870]

The intercepts and the graph on your worksheet are not correct. Please see below for details:

x^2-2x-3=0 has solutions at x=-1 and x=3 (use the quadratic formula to solve). That means these are the x-intercepts, namely points:

(-1,0) and (3,0).

The y-intercept comes from setting x=0 and calculating the y value:

y=0^2-2\cdot0-3=-3

so the y-intercept is (0,-3).

Now to the graph: Based on the form of the function we can see this is a quadratic function and its graph will be a parabola. You can reformat the expression in the following form

y = x^2-2x-3=(x-1)^2-4

and that will indicate that the apex of the parabola (open up) will be at the point (1,-4).

Knowing the apex, the x intercepts, and the y intercept, we can graph it now.

Graph is in the image attached.

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What is an irrational number
timofeeve [1]

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A dress needs 3 1/4 yards of fabric to make. If the matching jacket requires 5/6 less yards of fabric. How much fabric is needed
oksian1 [2.3K]
Fabric needs to make a dress = 3 1/4
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suppose a charity received a donation of $22.8 million. if this represents 58% of the charity's donated fund, what is the total
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The total amount is "x", so, if 22.8 is 58%, "x" is the 100%,

\bf \begin{array}{ccllll}&#10;amount&\%\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;22.8&58\\&#10;x&100&#10;\end{array}\implies \cfrac{22.8}{x}=\cfrac{58}{100}\implies \cfrac{22.8\cdot 100}{58}=x
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