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sdas [7]
3 years ago
12

What is the solution to the system of equations

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Hello,

Please, see the attaced file.

Thanks.

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Please help me thank you so much i will give brainliest answer if you get it right
Setler79 [48]

Answer:

the first four

Step-by-step explanation:

The last two do not equal 9 or .90

7 0
3 years ago
Express each of the following percentages as a fraction. 45%
vesna_86 [32]

Answer:

9/20

Step-by-step explanation:

45% can be written as

= 45/100

= 9/20

Hope it will help u..

3 0
3 years ago
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Please help me with this question I’m stuck going to get this right because it’s a quiz
Leno4ka [110]

Answer: True

Step-by-step explanation:

AB is congruent to RS

BC is congruent to ST

CD is congruent to TV

So DC would be congruent to VT

6 0
3 years ago
A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0
3 years ago
Find the zeros of polynomial functions and solve polynomials equations.<br> f(x)=2x^3+2x^2-4x
vladimir2022 [97]

f(x)=2x^3+2x^2-4x

The zeros of polynomial functions

2x^3 + 2x^2 - 4x = 0

2x(x^2 + x - 2) = 0

2x(x - 1)(x + 2) = 0

2x = 0; x = 0

x - 1 = 0; x = 1

x + 2 = 0; x = -2

Answer

x = -2 , 0 , 1


4 0
3 years ago
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