Make the table and cross multiply
Help me in this algebra1 problem
1 answer:
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Answer:
(4, 7 )
Step-by-step explanation:
y = 3x - 5 → (1)
y = x + 5 ( multiply through by 2 to clear the fraction )
2y = x + 10 → (2)
Substitute y = 3x - 5 into (2)
2(3x - 5) = x + 10 ← distribute parenthesis on left side
6x - 10 = x + 10 ( subtract x from both sides )
5x - 10 = 10 ( add 10 to both sides )
5x = 20 ( divide both sides by 5 )
x = 4
Substitute x = 4 into (1) and evaluate for y
y = 3(4) - 5 = 12 - 5 = 7
solution is (4, 7 )
