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Sphinxa [80]
3 years ago
14

the table lists information about four devices which lists the devices in order from greatest magnetic field strength to weakest

Physics
2 answers:
iren2701 [21]3 years ago
7 0

Answer:

X, Y, Z, W

Explanation:

edge 2020

SSSSS [86.1K]3 years ago
5 0

Answer:

<h2>D. X, Y, Z, W</h2>

Explanation: just took the quiz :)

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In the first stage of a two-stage Carnot engine, energy is absorbed as heat Q1 at temperature T1 = 500 K, work W1 is done, and e
Nataly [62]

Answer:

Efficiency = 52%

Explanation:

Given:

First stage

heat absorbed, Q₁ at temperature T₁ = 500 K

Heat released, Q₂ at temperature T₂ = 430 K

and the work done is W₁

Second stage

Heat released, Q₂ at temperature T₂ = 430 K

Heat released, Q₃ at temperature T₃ = 240 K

and the work done is W₂

Total work done, W = W₁ + W₂

Now,

The efficiency is given as:

\eta=\frac{\textup{Total\ work\ done}}{\textup{Energy\ provided}}

or

Work done = change in heat

thus,

W₁ = Q₁ - Q₂

W₂ = Q₂ - Q₃

Thus,

\eta=\frac{(Q_1-Q_2)\ +\ (Q_2-Q_3)}{Q_1}}

or

\eta=1-\frac{(Q_1-Q_3)}{Q_1}}

or

\eta=1-\frac{(Q_3)}{Q_1}}

also,

\frac{Q_1}{T_1}=\frac{Q_2}{T_2}=\frac{Q_3}{T_3}

or

\frac{T_3}{T_1}=\frac{Q_3}{Q_1}

thus,

\eta=1-\frac{(T_3)}{T_1}}

thus,

\eta=1-\frac{(240\ K)}{500\ K}}

or

\eta=0.52

or

Efficiency = 52%

8 0
4 years ago
3- A ball of mass 0,50 kg falls and hits the floor at 10m/s,
Klio2033 [76]

Answer:

3- A ball of mass 0,50 kg falls and hits the floor at 10m/s,

It rebounds at speed 8.0 m/s, as shown.

before collision

after collision

10 m/s

8 m/s

The collision between the ball and the floor lasts for 0.50 s.

What is the average force acting on the ball during the collision?

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3 years ago
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iVinArrow [24]

Answer:

D

D

C

C

Explanation: BRAINLIEST ME

6 0
3 years ago
A volleyball is hit upward with an initial velocity of 6.0 m/s. Calculate the displacement of the volleyball when its final velo
Nimfa-mama [501]

Answer:

1.78 m upward

Explanation:

We can find the displacement of the volleyball by using the SUVAT equation:

v^2 - u^2 = 2ad

where, assuming upward as positive direction:

u = 6.0 m/s is the initial velocity

v = 1.1 m/s is the final velocity

a = g = -9.8 m/s^2 is the acceleration of gravity

d is the displacement

Solving the equation for d, we find:

d=\frac{v^2-u^2}{2a}=\frac{1.1^2-6.0^2}{2(-9.8)}=1.78 m

And since it is positive, the displacement is upward.

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3 years ago
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