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Mkey [24]
4 years ago
6

The Work-in-Process limit at the Analyzing step of the Program Kanban is based on the overall availability of Product Management

, other subject matter experts, and the capacity of which two other roles?
Physics
1 answer:
NeX [460]4 years ago
7 0

Answer:

The Work-in-Process limit at the Analyzing step of the Program Kanban is based on the overall availability of Product Management, other subject matter experts, and the available development capacity and the VA time percentage of each process.

Explanation:

The term work-in-progress (WIP) describes partially finished goods or raw materials, labor, and overhead costs at several stages of the production process to be completed in a production and supply-chain management . WIP (Work in Progress) limits restrict and balance, through kanban board columns,the amount of production to match demand to capacity so workflow is increased all along the line helping it to finish faster avoiding bottlenecks focusing only on current tasks without new work taken on.

A Kanban board requires knowledge to provide a clear view of the WIP limit reached point but it also requieres discipline and commitment from employees.

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The principle of conservation of momentum is most similar to which of newton's laws of motion?
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You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its diameter to be 1.
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Answer:

Mass of the planet = 1.48 × 10²⁵ Kg

Mass of the star = 5.09 × 10³⁰ kg

Explanation:

Given;

Diameter = 1.8 × 10⁷ m

Therefore,

Radius = \frac{\textup{Diameter}}{\textup{2}}  = \frac{\textup{1.8}\times10^7}{\textup{2}}

or

Radius of the planet = 0.9 × 10⁷ m

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free-fall acceleration = 12.2 m/s²

Now,

we have the relation

g = \frac{\textup{GM}}{\textup{R}^2}

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on substituting the respective values, we get

12.2 = \frac{6.67\times10^{-11}\times M}{(0.9\times10^7)^2}

or

M = 1.48 × 10²⁵ Kg

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T² = \frac{\textup{4}\pi^2}{\textup{G}M_{star}}(R_{star})^3

on substituting the respective values, we get

35164800² = \frac{\textup{4}\pi^2}{6.67\times10^{-11}\timesM_{star}}(2.2\times10^{11})^3

or

M_{star} = 5.09 × 10³⁰ kg

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