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Answer:
C) Both the charge on the plates of the capacitor and its capacitance would change.
Explanation:
The capacitance of parallel plate capacitor without dielectric material is given as;
A parallel plate capacitor with a dielectric between its plates has a capacitance given by;
where;
C is the capacitance
K is the dielectric constant
ε₀ is permittivity of free space
A is the area of the plates
d is the distance of separation of the two plates
- first point to note, is that the capacitance increases when dielectric material is inserted by a factor 'k'
Again, Q = CV (without dielectric material)
(with dielectric material)
- second point to note, is that charge stored in the plates increases due to presence of dielectric material.
Finally, we can conclude that both the charge on the plates of the capacitor and its capacitance would change.