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CaHeK987 [17]
3 years ago
13

Express each quotient in the simplest form. 20xy^3/6z divided by 2xy/18z^5

Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0
\dfrac{20xy^3}{6z}:\dfrac{2xy}{18z^5}=\dfrac{10xy^3}{3z}:\dfrac{xy}{9z^5}=\dfrac{10xy^3}{3z}\cdot\dfrac{9z^5}{xy}\\\\=\dfrac{10xy^3}{z}\cdot\dfrac{3z^5}{xy}=10y^2z^4\\\\\text{used:}\\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{a^n}{a^m}=a^{n-m}
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Use the given minimum and maximum data​ entries, and the number of​ classes, to find the class​ width, the lower class​ limits,
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Using proportions and the information given, it is found that:

  • The class width is of 14.375.
  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

-------------------------

  • Minimum value is 19.
  • Maximum value is of 134.
  • There are 8 classes.
  • The classes are all of equal width, thus the width is of:

W = \frac{134 - 19}{8} = 14.375

-------------------------

The intervals will be of:

19 - 33.375

33.375 - 47.750

47.750 - 62.125

62.125 - 76.500

76.500 - 90.875

90.875 - 105.250

105.250 - 119.625

119.625 - 134.

  • The lower class limits are: {19, 33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625}.
  • The upper class limits are: {33.375, 47.750, 62.125, 76.500, 90.875, 105.250, 119.625, 134}.

A similar problem is given at brainly.com/question/16631975

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