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Art [367]
3 years ago
10

I need help, what is x-4<5

Mathematics
2 answers:
zhenek [66]3 years ago
8 0

Answer:

X would be x < 9

Step-by-step explanation:

You would do this equation like any other equation, but with the equal sign being greater or less than. So you would add 4 on both sides to get x < 9

Tanya [424]3 years ago
7 0

Answer:

X<9

Step-by-step explanation:

So basically in x-4<5 you would add 4 to the other side and that would be 9.

Hence your final answer is x<9.

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chubhunter [2.5K]

Answer: 4(2x²+9) or i\frac{3\sqrt{2} }{2}

Step-by-step explanation:

To solve the equation by factoring, we want to set the equation to zero. In order to have the equation equal to zero, we want to add both sides by 36.

8x²=-36            [add both sides by 36]

8x²+36=0

When it comes to factoring, we want to pull out numbers or variables that are common in each term.

8x²+36=0         [take out a 4 in each term]

4(2x²+9)=0

It may seem that 2x²+9 can be factored further, it actually can't. This tells us that the factored form of the equation is 4(2x²+9)=0.

To solve the equation, we want to find the value of x. We already know the graph does not cross the x-axis because the y-intercept or vertex is (0,9).

4(2x²+9)=0       [divide both sides by 4]

2x²+9=0            [subtract both sides by 9]

2x²=-9               [divide both sides by 2]

x²=-9/2              [square root both sides]

x=\sqrt{-\frac{9}{2} } or x=i\frac{3\sqrt{2} }{2}

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Step-by-step explanation:

Let's define:

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R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

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R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

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Step-by-step explanation:

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