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Nadya [2.5K]
4 years ago
7

Find the slope and y-intercept from the table.

Mathematics
2 answers:
Arte-miy333 [17]4 years ago
4 0

Answer:

Slope is -2/1 and the y-intercept is 10

Alekssandra [29.7K]4 years ago
3 0
The slope is -2
the y-intercept is 10
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Stels [109]

Answer:

helikopter hi do you want in sex

8 0
3 years ago
A planet follows an elliptical path described by 16 x squared + 4 y squared = 64. A comet follows the parabolic path y equals x
saul85 [17]

Answer:

The comet might intersect the orbiting planet at (0, -4),(\pm\frac{\sqrt{31}}{2},\frac{15}{4}).

Step-by-step explanation:

Given that, a planet follows an elliptical path described by

16x^2+4y^2=64 .........(1)

A comet follows the parabolic path

y=x^2-4

x^2=y+4.........(2)

To find the intersecting point, we need to solve the above equations.

Putting  x^2=y+4  in the equation (1)

y+4+4y^2=64

\Rightarrow 4y^2+y+4-64=0

\Rightarrow 4y^2+y-60=0

\Rightarrow 4y^2+16y-15y-60=0

\Rightarrow 4y(y+4)-15(y+4)=0

\Rightarrow(y+4)(4y-15)=0

\Rightarrow y=-4, \frac{15}{4}

When y = -4 , then x^2=-4+4 \Rightarrow x=0

When y=\frac{15}{4}, then x^2=\frac{15}{4}+4 \Rightarrow x=\pm \frac{\sqrt{31}}{2}

The comet might intersect the orbiting planet at (0, -4),(\pm\frac{\sqrt{31}}{2},\frac{15}{4}).

5 0
3 years ago
A man wins in a gambling game if he gets two heads in five flips of a biased coin. the probability of getting a head with the co
Semenov [28]

The probability the man will win will be 13.23%. And the probability of winning if he wins by getting at least four heads in five flips will be 36.01%.

<h3>How to find that a given condition can be modeled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials.

Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

P(X = x) = ⁿCₓ pˣ (1 - p)⁽ⁿ⁻ˣ⁾

A man wins in a gambling game if he gets two heads in five flips of a biased coin. the probability of getting a head with the coin is 0.7.

Then we have

p = 0.7

n = 5

Then the probability the man will win will be

P(X = 2) = ⁵C₂ (0.7)² (1 - 0.7)⁽⁵⁻²⁾

P(X = 2) = 10 x 0.49 x 0.027

P(X = 2) = 0.1323

P(X = 2) = 13.23%

Then the probability of winning if he wins by getting at least four heads in five flips will be

P(X = 4) = ⁵C₄ (0.7)⁴ (1 - 0.7)⁽⁵⁻⁴⁾

P(X = 4) = 5 x 0.2401 x 0.3

P(X = 4) = 0.3601

P(X = 4) = 36.01%

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

4 0
2 years ago
A watermelon seed is 4mm long. How far would a line of 114 watermelon seeds stretch? Write your answer in meters.
Stella [2.4K]
Four hundred fifty six
8 0
3 years ago
6.87x + 8x - 1 =<br><br> 7.3x + 6x - 2 =
Lorico [155]

1. 11s²-21st

2. 4st-t²

3. 2x²+x³

4. 2x+2

5. 9x-3s-2t

6. 95x-1

7. 9x-2

8. 7s

9. 12-10x

10. 33x-4

11. 10t

8 0
3 years ago
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