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3 years ago

Find the complex zeros of the polynomial function, write f in factored form. f(x) =x^3-9x^2+31x-39

Mathematics

1 answer:

bezimeni [28]3 years ago

6 0

x = 3

zeros are: 3 + 2i, 3 - 2i

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Enter the value of n =<br> Enter the value of m =<br> Enter the value of x =

Firdavs [7]

Hello!

$\large\boxed{\text{n = 5, m = 9, x = 512}}$

An exponential expression in form $\sqrt[z]{x^{y} }$ can be rewritten as $x^{\frac{y}{z} }$ where "z" is the root and "y" is the power. For example:

$x^{\frac{2}{3} } = \sqrt[3]{x^{2} }$ .

We can apply this idea to this problem:

$(32)^{\frac{9}{5} } = (\sqrt[5]{32^{9} } )$

Therefore:

n = 5

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Simplify the expression:

$\sqrt[5]{32^{9} } = (\sqrt[5]{32} )^{9}$

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Therefore, the values of all letters are:

n = 5

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3 years ago

Express the following fraction in simplest form using only positive exponents.

ElenaW [278]

Answer:

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Step-by-step explanation:

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