Answer:
X = {8n – 7n – 1 : n ϵ N}
Y = {49 (n –1) : n ϵ N} — (1) [all terms divisible by 49]
X = {8n – 7n – 1}
= (1 + 7)n – 7n – 1
= 1 + nC1 7 + nC2 72 + ….. + nCn 7n – 7n – 1
= nC2 72 + …… + nCn 7n
= 49 [nC2 + nC3 7 + …. nCn 7n-2] — (2)
From (1) and (2),
X is divisible by 49.
Y has all multiples of 49.
X ⊂ Y
Hey. Let me help you on this one.
In order for us to solve this problem, we will need to determine how much money Luke has earned from the sales this month, and find the total amount of sales in dollars.
I will also be attaching an image to this answer in case you still don't understand the question, or need extra help with your studies.
We know that Luke's salary is $3500, and anything above that amount of money comes from sales he makes. We also know that he only gets 15% from sales. Let's determine how much he earned from sales this month.
Luke has earned $1260 from the sales he made. Since it's only 15% of the full amount, we need to convert this value to 100%. We can do this by finding 1% of the unknown number, and multiplying it by 100 to show the full amount of sales.
Let's find 1% of the total amount of sales. Since 1260 is 15% of the unknown total, let's divide it by 15.
Great. $84 is 1% of the total amount of sales. All we need to do is multiply it by 100 to show 100% of the total amount of sales.
Awesome. We now know the amount of sales in dollars that Luke has brought to the company.
Answer: Total amount of Luke's sales in dollars is $8400
20% of 52
Set up a proportion.
20/100 = 52/1
Divide
52*0.2 = 10.40
Final answer: 10.4
Okay so in this question it says to solve f(7). This means to plug in the 7 every where you see an x, so that it looks like this:
Then you'll solve it like a normal equation.
Hope this helped! Let me know if there is anything I need to clarify or explain more in depth!
Answer:
(2,9)
Step-by-step explanation:
The midpoint of a point is halfway between two points. The distance between the midpoint and point H is 3 because the distance from 5 to 8 is 3. Therefore 3 away from 5 would be 2.