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3 years ago

Given that m 2=103 what is m 4

Mathematics

1 answer:

Vinvika [58]3 years ago

3 0

M4 would be choice b I know this because I put it in the calculator

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Solve for c: <br> 12 - 9 + c = 12

enyata [817]

Step-by-step explanation:

12 - 9 + c = 12

-9 + c = 12 - 12

- 9 + c = 0

Therefore c = 9

Hope this helps.!

6 0

3 years ago

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Solve for x, y, and z

valentina_108 [34]

Answer:

bmjbn

Step-by-step explanation:

4 0

3 years ago

Use your calculator to evaluate the limit of x equals 1 to 3 of e raised to the x squared power, dx. Give your answer to the nea

xz_007 [3.2K]

The integral of e raised to x squared dx to the limit from 1 to 3 translating in equation we get
∫1-3 e^(X^2) dx.

Solving using scientific calculator, we have 1443.082471 or simply 1443.

<em>ANSWER: 1443</em>

7 0

3 years ago

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

I have a circle that has a diameter of 10 inches

Stells [14]

The area of the circle is 314.16

The formula is a= pi times the radius squared

3 0

3 years ago