Answer:
Chloroform= limiting reactant
0.209mol of CCl4 is formed
And 32.186g of CCl4 is formed
Explanation:
The equation of reaction
CHCl3 + Cl2= CCl4 + HCl
From the equation 1 mol of
CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4
From the question
25g of CHCl3 really with Cl2
Molar mass of CHCl3= 119.5
Molar mass of Cl2 = 71
Hence moles of CHCl3= 25/119.5 = 0.209mol
Moles of Cl2 = 25/71 = 0.352mol
Hence CHCl3 is the limiting reactant
Since 1 mole of CHCl3 gave 1mol of CCl4
It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4
Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g
This is known as a synthesis reaction. A+B->C
Hope this helps!
D. the potential energy of the reactants is low; the potential energy decreases gradually; then increases slightly.
Sodium carbonate contains 3 elements: Na, C, and O. Step 2: Determine how many atoms of each element are in the formula. Na, Co, is made up of Na, C, and O3, so Na.co, has 2 atoms of sodium (Na) 1 atom of carbon (C) and 3 atoms of oxygen (O).
