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lana [24]
3 years ago
5

The polymer formed from the monomer ch2=ch–cn is select one:

Chemistry
1 answer:
podryga [215]3 years ago
5 0
Answer:
             None of the given options show polymer made up of H₂C=CH-CN (Acrylonitrile).

Explanation:
                   Acrylonitrile (H₂C=CH-CN) which is a monomer on self linkage results in a large chain polymer called as Polyacrylonitrile.
                   The structure of Polyacrylonitrile is as follow,

                                             --(H₂C-CHCN-)n--

Where n shows the number of Acrylonitrile units joined together in the formation of Polyacrylonitrile. This polymerization reaction can take place by different mechanisms including free radical mechanism, acid catalyzed addition or base catalyzed addition reaction.

The polymerization is shown below,

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Which term describes atoms with<br> unpaired dots in their electron dot<br> diagrams?
IRISSAK [1]

Answer:

Radicals

Explanation:

A radical refers to a chemical specie that contains unpaired electrons in their dot electron diagrams.

Radicals contain an odd number of electrons. They are commonly called odd electron species.

Radicals participate in a number of important reactions. A typical example is the halogenation of alkanes in the presence of light.

Examples of radicals include; Br. , Cl. , F. etc

8 0
3 years ago
Why does atomic radii decrease as you move from the left to right across the period
artcher [175]

Answer:

This is because, within a period or family of elements, all electrons are added to the same shell.

5 0
2 years ago
Read 2 more answers
Write the complete balanced equation for the following reaction: Al + Fe(NO2)2 Fe + Al(NO2)3
algol13
The equation is already balanced.
7 0
3 years ago
The Ka for formic acid (HCO2H) is 1.8 × 10-4. What is the pH of a 0.35 M aqueous solution of sodium formate (NaHCO2)?
anzhelika [568]

Answer:

9.36

Explanation:

Sodium formate is the conjugate base of formic acid.

Also,

K_a\times K_b=K_w

K_b for sodium formate is K_b=\frac {K_w}{K_a}

Given that:

K_a of formic acid = 1.8\times 10^{-4}

And, K_w=10^{-14}

So,

K_b=\frac {10^{-14}}{1.8\times 10^{-4}}

K_b=5.5556\times 10^{-11}

Concentration = 0.35 M

HCOONa    ⇒     Na⁺ +    HCOO⁻

Consider the ICE take for the formate  ion as:

                                   HCOO⁻ + H₂O   ⇄   HCOOH + OH⁻

At t=0                              0.35                            -              -

At t =equilibrium           (0.35-x)                          x           x            

The expression for dissociation constant of sodium formate is:

K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}

5.5556\times 10^{-11}=\frac {x^2}{0.35-x}

Solving for x, we get:

x = 0.44×10⁻⁵  M

pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64

pH + pOH = 14

So,

<u>pH = 14 - 4.64 = 9.36</u>

5 0
3 years ago
By what process do electromagnetic waves release from the materials they contact?
Rudik [331]

Answer:

The photoelectric effect

Explanation:  hope it helps

5 0
3 years ago
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