Answer:
See balanced equations below
Explanation:
1. Mg(s) +2 HCL (aq) →MgCl₂ (aq) +H₂(g)
This is a single replacement reaction, involving an acid with a metal
2. 2Al(s) + 3H₂SO₄ (aq)→Al₂(SO₄)₃(aq) + 3H₂
3. 3 Zn (s) + 2H₃PO₄(aq)→ Zn₃(PO₄)₂ (aq) + 3H₂ (g)
4. 2Al(s) + 6HCL (aq)→2AlCl₃(aq) +3H₂ (g)
B.
1. 2KOH(aq) + MgCl₂→Mg(OH)₂ (aq) + 2KCl (aq)
2. 3NaOH (aq)+ Al(NO₃)₃ (aq)→Al(OH)₃(s) + 3 NaNO₃(aq) ---this is a precipitation reaction
3. BaBr₂(aq) + H₂SO₄→BaSO₄ (s) + 2Br⁻(aq)
4. Na₂S + 2HCl → 2NaCl (aq) + H₂S (g)
5. 3CaCl₂ +2K₃PO₄→ Ca₃(PO₄)₂+6KCl
6.Ba(NO₃)₂ + (NH₄)₂CO₃→ 2(NH₄)⁺(aq) +BaCO₃(s)
Answer: The answer is 68142.4 Pa
Explanation:
Given that the initial properties of the cylindrical tank are :
Volume V1= 0.750m3
Temperature T1= 27C
Pressure P1 =7.5*10^3 Pa= 7500Pa
Final properties of the tank after decrease in volume and increase in temperature :
Volume V2 =0.480m3
Temperature T2 = 157C
Pressure P2 =?
Applying the gas law equation (Charles and Boyle's laws combined)
P1V1/T1 = P2V2/T2
(7500 * 0.750)/27 =( P2 * 0.480)/157
P2 =(7500 * 0.750* 157) / (0.480 *27)
P2 = 883125/12.96
P2 = 68142.4Pa
Therefore the pressure of the cylindrical tank after decrease in volume and increase in temperature is 68142.4Pa
Answer:
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The answer is N - N.
Purely covalent bond is formed by sharing electrons of atoms with same electronegativity to meet the octet rule (2 or 8 electrons in the valence shell).
Ne is a noble gas and has already 8 electrons in the valence shell, so it will not form a Ne - Ne bond.
Na is an alkaly metal with 1 electron in the valence shell and it does not form a true ionic bond but what is known a metallic bond.
N is a gas that forms a diatomic molecule N - N by sharing the valence electrons in a purely covalent bond.
Ni - O is a metal - non metal compound so it has a ionic character.