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alexira [117]
2 years ago
14

How many molecules are in 4.5 moles of Ca(OH),?​

Chemistry
2 answers:
Fudgin [204]2 years ago
6 0
<h2>Answer:</h2>

We will use dimensional analysis to solve this.

We will need to know Avogadro's number, which is 6.02 × 10²³.

4.5 mol × \frac{6.02 * 10^{23} molecules}{1 mol} = 2.71 × 10²⁴ molecules.

There are <em>2.71 × 10²⁴ molecules </em>in 4.5 moles of Ca(OH).

Art [367]2 years ago
6 0
61 molecules will be the answer most definitely :)
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Question 15 How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution? 58.40 g 175.3 g 14.60 g 43.83 g
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Hi!

To make 500 mL of a 1,500 M solution of NaCl you'll require 43,83 g

To calculate that, you will need to use a conversion factor to go from the volume of the 1,500 M solution to the required grams. For this conversion factor, you'll use the definition for Molar concentration (M=mol/L) and the molar mass of NaCl. The conversion factor is shown below:

gNaCl=500mLsol* \frac{1L}{1000 mL}* \frac{1,500 mol NaCl}{1Lsol}* \frac{58,4428 g NaCl}{1 mol NaCl} \\ =43,83gNaCl

Have a nice day!
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