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alexira [117]
2 years ago
14

How many molecules are in 4.5 moles of Ca(OH),?​

Chemistry
2 answers:
Fudgin [204]2 years ago
6 0
<h2>Answer:</h2>

We will use dimensional analysis to solve this.

We will need to know Avogadro's number, which is 6.02 × 10²³.

4.5 mol × \frac{6.02 * 10^{23} molecules}{1 mol} = 2.71 × 10²⁴ molecules.

There are <em>2.71 × 10²⁴ molecules </em>in 4.5 moles of Ca(OH).

Art [367]2 years ago
6 0
61 molecules will be the answer most definitely :)
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A mass of 100.0 g of NaCl is added to 100.0 mL of water, but not all of it dissolves. A mass of 59.5 grams of NaCl solid remains
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Answer:

The molarity of the dissolved NaCl is 6.93 M

Explanation:

Step 1: Data given

Mass of NaCl = 100.0 grams

Volume of water = 100.0 mL = 0.1 L

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Molar mass NaCl= 58.44 g/mol

Step 2: Calculate the dissolved mass of NaCl

100 - 59. 5 = 40.5 grams

Step 3: Calculate moles

Moles NaCl = 40.5 grams / 58.44 g/mol

Moles NaCl = 0.693 moles

Step 4: Calculate molarity

Molarity = moles / volume

Molarity dissolved NaCl = 0.693 moles / 0.1 L

Molarity dissolved NaCl = 6.93 M

The molarity of the dissolved NaCl is 6.93 M

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