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irakobra [83]
3 years ago
5

Which of the following statements describe constructive interference

Chemistry
1 answer:
natulia [17]3 years ago
4 0
1.) Constructive interference is observed when two waves having same phase are interfered. 
2.) The resultant amplitude of the 2 waves is equal to sum of the amplitude of individual wave. 
3.) The amplitude of resultant wave is maximum than individual wave.

Hope this helps you.
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Low energy waves have (3 points)
Sergeeva-Olga [200]

Answer:

Low energy waves have <u>a long wavelength.</u>

Explanation:

Energy of wave is directly related to  the frequency while it is inversely proportional to the wavelength.

If any wave have high energy it will have high frequency and smaller wavelength.

If the wave have lower energy then it will have lower frequency and higher wavelength.

Mathematical relationship:

E = h. f

E = h. c/λ

E= energy

h = planck's constant

f = frequency

c = speed of light

λ = wavelength

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Which compound contains a double bond?
just olya [345]
The answer would be ethane (C2H4)
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ODIO POD
miss Akunina [59]

Answer:

\boxed{\text{40 mol Al}}

Explanation:

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n/mol:     20

\text{Moles of Al} = \text{20 mol Al$_{2}$O$_{3}$}\times \dfrac{\text{2 mol Al}}{\text{1 mol Al$_{2}$O$_{3}$}}= \textbf{40 mol Al}\\\text{You can produce }\boxed{\textbf{40 mol Al}}

8 0
3 years ago
Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1
givi [52]

According to Hasselbach-Henderson equation:

pH=pK_{a}+log\frac{[A^{-}]}{[HA]}

Here, [A^{-}] is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is CH_{3}COOK and acid is CH_{3}COOH thus, Hasselbach-Henderson equation will be as follows:

pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{2}{1}=5.06

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{3}=4.28

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{5}{1}=5.45

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{1}=4.76

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}

Also, pK_{a}=4.76

Putting the values in equation (1),

pH=4.76+log\frac{1}{10}=3.76

Therefore, pH of solution is 3.76.

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2 years ago
What are two functions of the cell membrane
Nimfa-mama [501]

Answer:

1 It gives the cell its structure

2 It regulates the materials that enter and leaves the cell

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3 years ago
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