Answer:
/2=1.41
/5=2.24
(a)^2+(b)^2=(c)^2
(1.41)^2+(b)^2=(2.24)^2
2+(b)^2=5
(b)^2=5-2
(b)^2=3
b=/3 or 1.73
Step-by-step explanation:
for a triangle, a missing value of the side can be found using pythagorean theorem which is (a)^2+(b)^2=(c)^2
replace it with the given value.
*note:(c)^2 should be the hypotenuse
inverse of +ve is -ve
inverse of square is square root
Answer:
-5.6
Step-by-step explanation:
first distribute the 2.5
also convert the 2/5 to decimal (0.4) because it's hard to work with both decimal and fraction
2.5y + 2.5*0.4 = -13
2.5y +1 = -13
y = -14/2.5 = -5.6
Answer:
y = 42
Step-by-step explanation:
Given that y varies directly as x then the equation relating them is
y = kx ← k is the constant of variation
To find k use an ordered pair from the table.
Using x = 2 when y = 12, then
12 = 2k ( divide both sides by 2 )
6 = k
y = 6x ← equation of variation
When x = 7, then
y = 6 × 7 = 42
Answer: 5 km walking and 30 km by bus
Step-by-step explanation:
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?
walking - 5km/h bus - 60km/h
distance walking - d₁ distance bus - d₂
time walking - t₁ time bus - t₂
d₁ + d₂ = 35
t₁ + t₂ = 1.5
v = d/t
vwalking = d₁/t₁
5 = d₁/t₁ ⇒ d₁ = 5t₁
vbus = d₂/t₂
60 = d₂/t₂ ⇒ d₂ = 60t₂
d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35
_________________________
5t₁ + 60t₂ = 35
t₁ + t₂ = 1.5 (*-5)
5t₁ + 60t₂ = 35
-5t₁ -5t₂ = -7.5 (+)
__________________________
55t₂ = 27.5
t₂ = 27.5/55 = 0.5 h
t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h
d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km
d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km
Answer:
49 kilometers
Step-by-step explanation:
Since he cycles 1 km for each trip, he will have cycled 21 km after 21 trips.
Add this to his existing amount of km:
28 + 21
= 49
So, he will have cycled a total of 49 kilometers
