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3 years ago

Distance between (2,4)and(1,0)

Physics

2 answers:

kupik [55]3 years ago

7 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ \sqrt{17} \: \: units}}}}}$

Explanation:

Let the points be A and B

Let A ( 2 , 4 ) be ( x₁ , y₁ ) and B ( 1 , 0 ) be ( x₂ , y₂ )

Finding the distance between these points

$\boxed{ \sf{distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {(1 - 2)}^{2} + {(0 - 4)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {( - 1)}^{2} + {( - 4)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{1 + 16}}}$

$\longrightarrow{ \sf{ \sqrt{17} }}$ units

Hope I helped!

Best regards! :D

nordsb [41]3 years ago

6 0

Answer:

By using distance formula

your answer is √17

Explanation:

√(1-2)^2+(0-4)^2

√(-1)^2+(-4)^2

√1+16 = √17

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Distance between (2,4)and(1,0)​

Distance between (2,4)and(1,0)