All categories

3 years ago

Distance between (2,4)and(1,0)

Physics

2 answers:

kupik [55]3 years ago

7 0

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{ \sqrt{17} \: \: units}}}}}$

Explanation:

Let the points be A and B

Let A ( 2 , 4 ) be ( x₁ , y₁ ) and B ( 1 , 0 ) be ( x₂ , y₂ )

Finding the distance between these points

$\boxed{ \sf{distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {(1 - 2)}^{2} + {(0 - 4)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{ {( - 1)}^{2} + {( - 4)}^{2} } }}$

$\longrightarrow{ \sf{ \sqrt{1 + 16}}}$

$\longrightarrow{ \sf{ \sqrt{17} }}$ units

Hope I helped!

Best regards! :D

nordsb [41]3 years ago

6 0

Answer:

By using distance formula

your answer is √17

Explanation:

√(1-2)^2+(0-4)^2

√(-1)^2+(-4)^2

√1+16 = √17

You might be interested in

Which location on the map above is a source of North Atlantic deep water?

bija089 [108]

The answer might be C ? hope it's right

4 0

3 years ago

A mass m is attached to a string connected to a force sensor on a rotating platform. The platform’s angular velocity, ω, can be

makkiz [27]

Answer:

The mass m is 0.332 kg or 332 gm

Explanation:

Given

The platform is rotating with angular speed , $\omega =8.5\, \frac{rad}{sec}$

Mass m is moving on platform in a circle with radius , $r=0.20\, m$

Force sensor reading to which spring is attached , $F=4.8\, N$

Now for the mass m to move in circle the required centripetal force is given by $F=m\omega ^{2}r$

=> $4.8=m\times 8.5 ^{2}\times 0.20$

$=>m=0.332\, kg$

Thus the mass m is 0.332 kg or 332 gm

7 0

3 years ago

A man pushing a mop across a floor causes it to undergo two displacements. The first has a magnitude of 152 om and makes an angl

aliya0001 [1]

Answer:

D₂= 167,21 cm : Magnitude of the second displacement

β= 21.8° , countercockwise from the positive x-axis: Direction of the second displacement

Explanation:

We find the x-y components for the given vectors:

i: unit vector in x direction

j:unit vector in y direction

D₁: Displacement Vector 1

D₂: Displacement Vector 2

R= resulta displacement vector

D₁= 152*cos110°(i)+152*sin110°(j)=-51.99i+142.83j

D₂= -D₂(i)-D₂(j)

R= 131*cos38°(i)+ 131*sin38°(j) = 103.23i+80.65j

We propose the vector equation for sum of vectors:

D₁+ D₂= R

-51.99i+142.83j+D₂x(i)-D₂y(j) = 103.23i+80.65j

-51.99i+D₂x(i)=103.23i

D₂x=103.23+51.99=155.22 cm

+142.83j-D₂y(j) =+80.65j

D₂y=142.83-80.65=62.18 cm

Magnitude and direction of the second displacement

$D_{2} =\sqrt{(D_{x})^{2} +(D_{y} )^{2} }$

$D_{2} =\sqrt{(155.22)^{2} +(62.18 )^{2} }$

D₂= 167.21 cm

Direction of the second displacement

$\beta = tan^{-1} \frac{D_{y}}{D_{x} }$

$\beta = tan^{-1} \frac{62.18}{155.22 }$

β= 21.8°

D₂= 167,21 cm : Magnitude of the second displacement

β= 21.8.° , countercockwise from the positive x-axis: Direction of the second displacement

6 0

4 years ago

All forces are different each exerts a particular type of effect on an object

prisoha [69]

Is this a true and false question?

7 0

4 years ago

A polonium isotope with an atomic mass of 211.988868 u undergoes alpha decay, resulting in a daughter isotope with an atomic mas

prisoha [69]

Answer:

K = 9.53 MeV

Explanation:

The kinetic energy that the alpha particle has emitted, is the energy in excess after removing the resting energy of the atoms and the helium nucleus that forms the alpha particle

Since energy and masses are related and cannot be

m₀ c² = $m_{f}$ c² + m_He c²+ K

K = c² (m₀ - m_{f} - m_He)

the mass of the Helium atom is 4 u

K = (3 10⁸)² (211,988868 -207.976652 - 4,002) 1,661 10⁻²⁷

K = 14,949 10⁻¹¹ (0.0102)

K = 1,527 10⁻¹² J

let's reduce 1 J = 6,242 10¹² MeV

K = 9.53 MeV

7 0

4 years ago

Distance between (2,4)and(1,0)​

Distance between (2,4)and(1,0)