We calculate the coordinates at t₁ = 9 min and t₂ = 10 min, since the 10th minute is between t₁ and t₂.
As it leaves from rest, it means that the initial speed is zero
t₁=9 min=540 s
t₂=10 min=600 s
x₁=at₁²/2=8*540²/2=4*291600=1166400 m
x₂=at₂²/2=8*600²/2=4*360000=1440000 m
Δx=x₂-x₁=1440000-1166400=273600 m represents the distance traveled by the car in the 10th minute of travel
Answer:
A. Moving the mass from Point C to B, although it involves a greater distance, requires less force to do the same amount of work.
Explanation:
The amount of work will be the same either way. By going from C to B, the mover will exert less force over a greater distance, which is easier than exerting a greater force over a shorter distance.
Answer:
s = 3.84 x 10⁸ m
Explanation:
The distance traveled by an object, while in uniform motion, is given by the following equation:
s = vt
where,
s = distance covered
v = speed
t = time interval
In this case:
s = distance between Moon and Earth = ?
v = speed of radio waves = 3 x 10⁸ m/s
t = time taken to travel = 1.28 s
Therefore,
s = (3 x 10⁸ m/s)(1.28 s)
<u>s = 3.84 x 10⁸ m</u>
To solve this problem, it is necessary to apply the concepts related to force described in Newton's second law, so that
F = ma
Where,
m = mass
a = Acceleration (Gravitational acceleration when there is action over the object of the earth)
Torque, as we know, is the force applied at a certain distance, that is,
Where
F= Force
d = Distance
Our values are given as,
Since the system is in equilibrium the difference of the torques is the result of the total Torque applied, that is to say
Therefore the magnitude of the frictional torque at the axle of the pulley if the system remains at rest when the balls are released is
