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3 years ago

The amount of energy needed to raise one gram of a substance one degree Celsius is a characteristic property known as

2 answers:

5 0

Answer : The amount of energy needed to raise one gram of a substance one degree Celsius is a characteristic property known as, Specific heat capacity.

Explanation:

Heat capacity : It is defined as the heat required to raise the temperature by one degree.

Specific heat capacity : It is defined as the amount of heat required by one gram of a substance to raise its temperature by one degree Celsius.

The heat required to change the temperature of a substance is related to heat capacity of the substance by the expression as :

$C=\frac{q}{m\times \Delta T}$

where,

C = specific heat capacity

m = mass of a substance

q = heat required

$\Delta T$ = change in temperature of substance

Hence, the amount of energy needed to raise one gram of a substance one degree Celsius is a characteristic property known as, Specific heat capacity.

inna [77]3 years ago

4 0

The answer is heat capacity.

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In what kind of reaction does one element replace a similar element in a compound?

andriy [413]

I believe what you are talking about is the synthesis reaction

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4 years ago

How many atoms are in 766.3 grams of Li?

34kurt

1 mol of any substance is made of 6.022 x 10²³ units, these units could be atoms making up elements or molecules making up a compound.

In this case. 1 mol of Li is made of 6.022 x 10²³ atoms of Li

The molar mass of Li is 6.94 g/mol

Therefore mass of 1 mol of Li is 6.94 g

In 6.94 g of Li there are - 6.022 x 10²³ atoms

Then in 766.3 g of Li there are - 6.022 x 10²³ atoms / 6.94 g x 766.3 g = 665 x 10²³

There are 6.65 x 10^25 atoms of Li

6 0

4 years ago

What does the hydrosphere include? Glaciers Groundwater Lava Polar Ice

Darya [45]

Answer:

Groundwater, Glaciers, and Polar Ice.

Explanation:

3 0

3 years ago

C3H8 + O2 → CO2 + H2O

andreyandreev [35.5K]

First, we'll balance the equation
C3H8 + 5O2 --> 3CO2 + 4H2O
Next, we know that a gas at stp occupies 22.4 liters/mole, so we can find the number of moles of oxygen gas.
15 liters O2 * (1 mole O2)/(22.4 liters O2) = 0.67 moles O2
Now we know from our balanced equation that there are 3 moles of CO2 per mole of O2, so we can find the number of moles of CO2 we produce.
0.67 moles O2 * (3 moles CO2/5 moles O2) = 0.40 moles CO2
Now, we have the number of moles of CO2, and we know that one mole occupies 22.4 liters, we can find the number of liters
.40 moles CO2 * (22.4 liters CO2)/(1 mole CO2) = 9.0 liters of CO2
The answer is D

4 0

3 years ago

In pure water at 25 °C, the concentration of a saturated solution of CuF2 is 7.4 × 10−3 M. If measured at the same temperature,

Romashka-Z-Leto [24]

Answer:

The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is 4.0×10⁻⁵ M.

Explanation:

Consider the ICE take for the solubility of the solid, CuF₂ as:

CuF₂ ⇄ Cu²⁺ + 2F⁻

At t=0 x - -

At t =equilibrium (x-s) s 2s

The expression for Solubility product for CuF₂ is:

$K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2$

$K_{sp}=s\times {2s}^2$

$K_{sp}=4s^3$

Given s = 7.4×10⁻³ M

So, Ksp is:

$K_{sp}=4\times (7.4\times 10^{-3})^3$

Ksp = 1.6209×10⁻⁶

Now, we have to calculate the solubility of CuF₂ in NaF.

Thus, NaF already contain 0.20 M F⁻ ions

Consider the ICE take for the solubility of the solid, CuF₂ in NaFas:

CuF₂ ⇄ Cu²⁺ + 2F⁻

At t=0 x - 0.20

At t =equilibrium (x-s') s' 0.20+2s'

The expression for Solubility product for CuF₂ is:

$K_{sp}=\left [ Cu^{2+} \right ]\left [ F^- \right ]^2$

$1.6209\times 10^{-6}={s}'\times ({0.20+2{s}'})^2$

Solving for s', we get

s' = 4.0×10⁻⁵ M

The concentration of a saturated solution of CuF₂ in aqueous 0.20 M NaF is 4.0×10⁻⁵ M.

3 0

4 years ago