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Sever21 [200]
3 years ago
10

•In carrying out an experiment based on this reaction, 2.45 L of dinitrogen tetroxide were used. How many liters of nitrogen dio

xide are produced? Temperature and pressure were held constant. Work must be shown in order to earn credit.
Chemistry
1 answer:
lapo4ka [179]3 years ago
3 0
Dinitrogen  tetroxide   decomposes  to   give  nitrogen  dioxide  according  to   equation  below
N2O4--->2NO2
According  to  avogadros law
1 moles  =22.4  l
what  about  2.45 l
=2.45l  x1  mole/22.4=0.1094 moles
by  use  of  reacting  ratio  that  1 :2
the  moles of  No2  =  0.1094  x2=0.2188 moles

1 moles=  22.4 l
what  about  0.2188moles
=(0.2188moles x22.4  l) /1moles=4.90  L
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Setler [38]

Answer:

1.7927 mL

Explanation:

The mass of solid taken = 4.75 g

This solid contains 21.6 wt% Ba(NO_3)_2, thus,

Mass of Ba(NO_3)_2 = \frac {21.6}{100}\times 4.75\ g = 1.026 g

Molar mass of Ba(NO_3)_2 = 261.337 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.026\ g}{261.337\ g/mol}

Moles= 0.003926\ mol

Considering the reaction as:

Ba(NO_3)_2+H_2SO_4\rightarrow BaSO_4+2HNO_3

1 moles of Ba(NO_3)_2 react with 1 mole of H_2SO_4

Thus,

0.003926 mole of Ba(NO_3)_2 react with 0.003926 mole of H_2SO_4

Moles of H_2SO_4 = 0.003926 mole

Also, considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity = 2.19 M

So,

2.19=\frac{0.003926}{Volume\ of\ the\ solution(L)}

Volume = 0.0017927 L

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Question 1
REY [17]

Answer:

An atom of neon-20 has one fewer proton and two fewer neutrons than an atom of sodium-23.

Explanation:

Neon - 20 and Sodium - 23

Neon - 20

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Neutrons = 10

Sodium - 23

Protons = 11

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With the information above and checking the options;

An atom of neon-20 has one fewer proton and two fewer neutrons than an atom of sodium-23.

This option is correct.

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I think it's easiest to find the pOH from the given [OH-] first.

-log(1x10^-5)

pOH=5

Then find the pH.

pOH+pH=14

5+pH=14

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Then find the [H+] using the pH.

antilog(-9) (if you dont have an antilog button use 10^-9)

[H+]=1x10^-9

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Answer:

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