Answer:
C6H14 < C6H13Br < C6H13OH < C6H12(OH)2
Explanation:
Hello,
In this case, since the solubility in water is related with the presence of polar bonds in the given molecules we can see that C6H12(OH)2 has the presence two O-H bonds which promote the highest solubility via hydrogen bonds as well as the C6H13OH but in a lower degree as only on O-H bond is present. Next since the bond C-Br in is slightly close to the polar bond C6H13Br rather than the C-C bonds only had by C6H14 we can infer that C6H13Br is more soluble in water than C6H14, therefore the required order is:
C6H14 < C6H13Br < C6H13OH < C6H12(OH)2
Whereas C6H12(OH)2 is the most soluble and C6H14 the least soluble in water.
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Answer:
The pressure is 0,97 atm
Explanation:
We apply Boyle Mariotte's Law, where for a certain mass of gas, at constant temperature, the pressure and volume vary inversely proportionally: P1x V1 = P2 x V2 P2= (P1 x V1)/V2
P2 = 1, 50 atm x 5, 00 L /7,74 L
P2= 0, 97 atm
Answer:
B. 1 triple bond and 2 single bonds
Explanation:
C2Cl2 has linear structure.
For its Lewis structure, the C2Cl2 molecule has a total of 22 valence electrons. Each Carbon (C) atom has 4 valence electrons and 7 atoms in each chlorine atoms.
So, after pairing in C2Cl2, Chlorine (Cl) form 2 single bonds, one with each carbon atom andboth the Carbon (C) atoms form one triple bond with each other.
