Question

Which of the following 100.0-g samples contains the greatest number of atoms?a.Magnesiumb.Zincc.Silverd.Calciume.All samples contain the same number of atom

Answer 1

Answer: The correct answer is (a)Magnesium

Explanation:

Step 1:

Calculate the number of moles of each of the samples mentioned.

a)Magnesium

n=mass/atomic mass

n=100.0/24.305

n=4.11 moles

b)Zinc

n=100.0/65.38

n=1.53 moles

c)Silver

n=100.0/107.87

n=0.93 moles

d)Calcium

n=100/40.078

n= 2.30 moles

Step 2

Find the number of atoms by multiplying no. of moles with avogadro's number

a)Magnesium

no. of atoms=4.11 * 6.022*10^23

= 2.45*10^24 atoms

b)Zinc

no. of atoms=1.53 * 6.022*10^23

= 9.21*10^23 atoms

c)Silver

no. of atoms=0.93 * 6.022*10^23

=5.60*10^23 atoms

d)Calcium

no. of atoms=2.30 * 6.022*10^23

=1.39*10^24 atoms

As pet the above calculations, sample of Magnesium contains the highest number of atoms

Answer 2

Explanation:

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