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k0ka [10]
3 years ago
7

At Elisa's printing company, there are two kinds of printing presses: Model A, which can print 70 books/ day, and model B, which

can print 55 books per day. The company owns 14 total printing presses that allow them to print 905 books per day. How many model A presses do they have?
Mathematics
1 answer:
Dmitrij [34]3 years ago
3 0

Answer:

9 Model As.

Step-by-step explanation:

Let A represent Press A and let B represent Press B.

So, they own 14 total presses. This means that:

A+B=14

They can print 905 books per day, in other words, since A prints 70 per day and B prints 55 per day:

70A+55B=905

This is now a system of equations. Solve by substitution. From the first equation, subtract B from both sides:

A=14-B

Substitute this into the second equation: "

70(14-B)+55B=905

First, we can divide everything by 5 to simplify things:

14(14-B)+11B=181

Distribute the left:

196-14B+11B=181

Combine like terms:

-3B+196=181

Subtract 196 from both sides:

-3B=-15

Divide both sides by -3

B=5

So, the company has 5 Model B presses.

Which means that the company has 14-5 or 9 Model A presses.

And we're done!

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3 years ago a father was 3 times as old as his son, in five years time he will be twice as old as his son, what will be the sum
ivolga24 [154]

Answer: 46 years

Step-by-step explanation:

Let the father's age be x and the son's age be y, then 3 years ago:

Father = x - 3

son     = y - 3

Then , from the first statement :

x - 3 = 3 ( y - 3 )

x - 3 = 3y - 9

x     = 3y - 9 + 3

x     = 3y - 6 .......................................... equation 1

In five years time

father = x + 5

son = y + 5

Then , from the second statement

x + 5 = 2 ( y + 5 )

x + 5 = 2y + 10

x       = 2y + 10 - 5

x       = 2y + 5 ........................ equation 2

Equating equation 1 and 2 , we have

3y -6 = 2y + 5

add 6 to both sides

3y = 2y + 5 + 6

subtract 2y from both sides

3y - 2y = 11

y = 11

substitute y = 11 into equation 1 to find the value of x

x = 3y - 6

x = 3(11) - 6

x = 33 - 6

x = 27

This means that the father is presently 27 years and the son is presently 11 years.

In four years time

father = 27 + 4 = 31

son = 11 + 4      = 15

sum of their ages in four years time will be

31 + 15 = 46 years

5 0
3 years ago
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Jade drinks 1/4 of a full bottle of water. An hour later she drinks 1/6 of the original volume. What fraction remains?
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She drinks 1/4th of the bottle and then another 1/6th of the bottle. So he drinks 3/12+2/12 of a bottle which is 5/12
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The school will not announce a snow day unless there is 10 inches of snow on the ground. If it had already snowed 1.5 inches how
Dennis_Churaev [7]
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3 years ago
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Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
3 years ago
Given: Triangle ABC with vertices A(5,-2), B(5.-7), and C(1, -2). Which set of
BigorU [14]

Answer: C (0,0), (-4,0) and (0, -5)

Step-by-step explanation:

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