Answer: I think the answer is D.
Positively charged particles.
Answer:
(1) 42.94 m
(2) 
Explanation:
Let us first draw a figure, for the given question as below:
In the figure, we assume that the person starts walking from point A to travel 11 m exactly
south of west to point B and from there, it walks 21 m exactly
west of north to reach point C.
Let us first write the two displacements in the vector form:

Now, the vector sum of both these vectors will give us displacement vector from point A to point C.

Part (1):
the magnitude of the shortest displacement from the starting point A to point the final position C is given by:

Part (2):
As the vector AC is coordinates lie in the third quadrant of the cartesian vector plane whose angle with the west will be positive in the north direction.
The angle of the shortest line connecting the starting point and the final position measured north of west is given by:

the answer would be C
work done = force * distance
wd = 3*2
wd = 6 J
wd = 2*3
wd = 6 J
so the work done is the same
Answer:
520 N
Explanation:
Work is the dot product of the force vector and displacement vector.
W = F · x
This means it is the product of the magnitudes of the vectors and the cosine of the angle between them.
W = F x cos θ
The displacement of the soil is 15 m up. The force is parallel to the ramp. So the angle between the vectors is 90° − 35° = 55°.
Plugging in the values and solving for F:
4500 J = F (15 m) (cos 55°)
F = 523 N
Rounded to two significant figures, the force is 520 N.