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1 year ago

A particle is moving at a speed less than c / 2 . If the speed of the particle is doubled, what happens to its momentum?

Physics

1 answer:

Semenov [28]1 year ago

3 0

If the speed of the particle is doubled. Then the value of the momentum also gets doubled.

<h3>What is momentum?</h3>

The sum of an entity's speed and mass is known as its linear momentum, translational momentum, or simply momentum in Newton's laws of motion. It has both a magnitude and a direction, making it a vector quantity. The SI unit of momentum is kg-m / s.

Let m be the mass and v be the velocity of an object. Then the momentum is given as,

P = mv kg-m / s

A particle is moving at a speed less than c / 2. If the speed of the particle is doubled.

P = m(2v)

P = 2mv

If the particle's speed is twice. The momentum's value is then increased by two.

More about the momentum link is given below.

brainly.com/question/24030570

#SPJ1

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marshall27 [118]

Answer:

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<h3>Hope this helps.</h3><h3>Good luck ✅.</h3>

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1 year ago

Use the slit example to explain why you can hear a noise in another room through an open door.

defon

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3 years ago

After rubbing a balloon on your shirt, your hair sticks up when the balloon is near your head. Explain how tiny particles on you

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1 year ago

You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state

posledela

Answer:

a) y₂ = 49.1 m , t = 1.02 s , b) y = 49.1 m , t= 1.02 s

Explanation:

a) We will solve this problem with the missile launch kinematic equations, to find the maximum height, at this point the vertical speed is zero

$v_{y}$ ² = $v_{oy}$ ² - 2 g (y –yo)

The origin of the coordinate system is on the floor and the ball is thrown from a height

y-yo = $v_{oy}² /2 g
 y- 0 = 10.0²/2 9.8
 y - 0 = 5.10 m
 
The height from the ground is the height that rises from the reference system plus the depth of the ground from the reference system
 y₂ = 5.1 + 44
 y₂ = 49.1 m
Let's use the other equation to find the time
 [tex]v_{y}$ = $v_{oy}$ - g t

t = $v_{oy}$ / g

t = 10 / 9.8

t = 1.02 s

b) the maximum height

y- 44.0 = $v_{y}$ ² / 2 g

y - 44.0 = 5.1

y = 5.1 +44.0

y = 49.1 m

The time is the same because it does not depend on the initial height

t = 1.02 s

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3 years ago

A 75 W lightbulb is being run on a 110 V outlet. Determine the resistance of the lightbulb. Provide a detailed description of th

Sauron [17]

Power is defined as

P = I*V

where I is the current and V is the voltage

Ohm's law gives us the relation betwen Voltage and current in a resistive component

V = I*R , Then

P = V² / R

We solve for R,

R = (110 V)²/ 75W = 161.33 ohms

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2 years ago