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2 years ago

A particle is moving at a speed less than c / 2 . If the speed of the particle is doubled, what happens to its momentum?

Physics

1 answer:

Semenov [28]2 years ago

3 0

If the speed of the particle is doubled. Then the value of the momentum also gets doubled.

<h3>What is momentum?</h3>

The sum of an entity's speed and mass is known as its linear momentum, translational momentum, or simply momentum in Newton's laws of motion. It has both a magnitude and a direction, making it a vector quantity. The SI unit of momentum is kg-m / s.

Let m be the mass and v be the velocity of an object. Then the momentum is given as,

P = mv kg-m / s

A particle is moving at a speed less than c / 2. If the speed of the particle is doubled.

P = m(2v)

P = 2mv

If the particle's speed is twice. The momentum's value is then increased by two.

More about the momentum link is given below.

brainly.com/question/24030570

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2 years ago

A 2100 kg car starts from rest and accelerates at a rate of 2.6 m/s2 for 4.0 s. Assume that the force acting to accelerate the c

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3 years ago

In a choir practice room, two parallel walls are 5.70 m apart. The singers stand against the north wall. The organist faces the

ololo11 [35]

Answer:

4.98 m

Explanation:

Given that

Width of the mirror, d = 0.6 m

Organist distance to the mirror, s = 0.78 m

Distance between the singer and the organist, S = 5.7 + 0.78 = 6.48 m

Width of north wall, D?

Using the simple relationship

D/S = d/s, on rearranging

D = dS /s

D = (0.6 * 6.48) / 0.78

D = 3.888 / 0.78

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3 years ago

The term pressure most nearly refers to which of the following?

Arte-miy333 [17]

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3 years ago

Read 2 more answers

A submarine is 2.84 102 m horizontally from shore and 1.00 102 m beneath the surface of the water. A laser beam is sent from the

xxMikexx [17]

Answer:

468 m

Explanation:

So the building and the point where the laser hit the water surface make a right triangle. Let's call this triangle ABC where A is at the base of the building, B is at the top of the building, and C is where the laser hits the water surface. Similarly, the submarine, the projected submarine on the surface and the point where the laser hit the surface makes a another right triangle CDE. Let D be the submarine and E is the other point.

The length CE is length AE - length AC = 284 - 234 = 50 m

We can calculate the angle ECD:

$tan(\hat{ECD}) = \frac{ED}{EC} = \frac{100}{50} = 2$