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erica [24]
3 years ago
6

Which two optical devices use convex lenses to focus and enlarge images?

Physics
1 answer:
Andreas93 [3]3 years ago
4 0
It is a reflecting telescope and a compound microscope. I know this for sure
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Two objects have a force of gravity of 100 N. If the distance between both objects decreases by a factor of 7, while the masses
Shkiper50 [21]

The gravitational force <em>F</em> between two masses <em>M</em> and <em>m</em> a distance <em>r</em> apart is

<em>F</em> = <em>G M m</em> / <em>r</em> ²

Decrease the distance by a factor of 7 by replacing <em>r</em> with <em>r</em> / 7, and decrease both masses by a factor of 8 by replacing <em>M</em> and <em>m</em> with <em>M</em> / 8 and <em>m</em> / 8, respectively. Then the new force <em>F*</em> is

<em>F*</em> = <em>G </em>(<em>M</em> / 8) (<em>m</em> / 8) / (<em>r</em> / 7)²

<em>F*</em> = (1/64 × <em>G M m</em>) / (1/49 × <em>r</em> ²)

<em>F*</em> = 49/64 × <em>G M m</em> / <em>r</em> ²

In other words, the new force is scaled down by a factor of 49/64 ≈ 0.7656, so the new force has magnitude approx. 76.56 N.

8 0
3 years ago
Two dimensional motion is not always projectile motion. In two dimensional motion that is not projectile motion, what is not acc
MatroZZZ [7]

gravity is the correct answer.

4 0
3 years ago
Read 2 more answers
Definition of complex machine
ASHA 777 [7]
A complex machine is a machine made up of two or more simple machines that make your work easier to do. There are six simple machines from which all complex machines are made. They include: The lever. The inclined plane
4 0
2 years ago
Read 2 more answers
Can you have a changing speed and constant velocity?
igor_vitrenko [27]
No, a body can not have its velocity constant, while its speed varies. Rather, it can have its speed constant and its velocity varying. For example in a uniform circular motion.

7 0
3 years ago
Una flecha tiene una rapidez de lanzamiento inicial de 18 m/s. Si debe dar en un blanco a 31 m de distancia, que está a la misma
maks197457 [2]

Answer:

34.8 and 55.2º

Explanation:

This is a projectile launching exercise, as we are told that the range of the arrow must be equal to its range and = 31 m let's use the equation

         

The scope equation is

         R = v₀² sin 2θ /g

         sin 2 θ = R g / v₀²

         sin 2 θ = 31 9.8 / 18²

         2 θ = sin⁻¹ 0.93765

          θ = 34.8º

At the launch of projectiles we have two complementary angles with the same range in this case 34.8 and (90-34.8) = 55.2º

4 0
3 years ago
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