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erica [24]
3 years ago
6

Which two optical devices use convex lenses to focus and enlarge images?

Physics
1 answer:
Andreas93 [3]3 years ago
4 0
It is a reflecting telescope and a compound microscope. I know this for sure
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You flip a coin straight up if the coin reaches a high point of 0.25 m above where you released it what was the initial speed?
Julli [10]

Answer: 2.21 m/s

Explanation:

Given

Coin reaches a height of  0.25 m above the launch point

Suppose u is the initial speed of the coin

Using the equation of motion

\Rightarrow v^2-u^2=2as\\

Putting values

\Rightarrow 0^2-u^2=2\times g\times s=2\times (-9.8)\times 0.25\\\Rightarrow u^2=4.9\\\Rightarrow u=2.21\ m/s

Thus, the initial velocity is 2.21 m/s

6 0
3 years ago
Aye yo help me out plz
Lilit [14]

Answer:

B

Explanation:

3 0
3 years ago
Read 2 more answers
Think of a skateboarder riding down a hill. Once the skateboarder reaches the bottom of the hill, if she does not manually add m
ivanzaharov [21]

From first law of motion, law of inertia, we know that an object remains in the state of rest or motion unless acted upon by an unbalanced external force. The skateboard riding down a hill when reaches the bottom slows down due to <u>frictional force </u>acting in the opposite direction. Frictional force is a contact force which acts between two surfaces against the direction of  motion of one surface over the other. Here, frictional force acts <u>between skateboard and ground</u>. This reduces the speed of the skateboard and it eventually stops.

8 0
4 years ago
Read 2 more answers
Takes 5 seconds and 2,000 J for a crane to lift a very heavy object. Which of these correctly describes power and energy for thi
strojnjashka [21]

Answer:

D

Explanation

take 5x2000 and J is the unit for power therfore it cant be A and B and C are not 10,000.

8 0
3 years ago
A car traveling 90km/hr is 100 m behind a truck traveling 50km/hr. How long will it take the car to reach the truck?
AlexFokin [52]

The faster car behind is catching up/closing the gap/gaining on
the slow truck in front at the rate of (90 - 50) = 40 km/hr.

At that rate, it takes (100 m) / (40,000 m/hr) = 1/400 of an hour
to reach the truck.

(1/400 hour) x (3,600 seconds/hour) = 3600/400 = <em>9 seconds</em>, exactly 


4 0
4 years ago
Read 2 more answers
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