Ask question

Ask question

All categories

3 years ago

14

A boat leaves port traveling 22 mph. Then, 18 minutes later, a second boat leaves port traveling 28 mph on the same heading as t

he first boat. How far from port does the second boat overtake the first boat? A - 30.2 B - 30.8 C - 30.6 D - 30.5 E - 30.4

1 answer:

bazaltina [42]3 years ago

7 0

Answer:

Step-by-step explanation:25

You might be interested in

V square+6v-59=0<br> answer in one equation

Tema [17]

X= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$
a=1
b=6
c=-59
x= $\frac{-6+/- \sqrt{(6)-4(1)(-59)} }{2(1)}$
x= $-3+ 2\sqrt{17}$ and $-3- 2\sqrt{17}$

8 0

3 years ago

No links or files or ima report you and i mean it

mihalych1998 [28]

Answer: Links and files

6 0

3 years ago

The cost of 5 books is 71$ . What is the cost of each book

Alla [95]

$14.20 is the cost of each book

3 0

3 years ago

Read 2 more answers

The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem

lyudmila [28]

If $\mathcal C$ is the boundary of the triangle $D$ , then by Green's theorem

$\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA$
$=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x\int_{y=0}^{y=2x}(2y^3-1)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x(8x^4-2x)\,\mathrm dx=\frac23$

4 0

3 years ago

Javier drove 45 miles. This represent 60% of his entire trip. What is the total number of miles in Javier’s trip

Andrews [41]

60% of trip = 45 miles

let total trip distance = l

60% is given by multiplying by 0.6

So;

0.6l = 45 \\ \\ l = \frac{45}{0.6} \\ \\ \boxed{l = 75}

Your answer is 75 miles

8 0

3 years ago

Read 2 more answers