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2 years ago

6

The earth travels one full rotation around the sun in approximately 365.25 days. How many minutes does it take for the earth to

travel ine full rotation around the sun? Show your work. Make sure to included units in your answer.

1 answer:

VashaNatasha [74]2 years ago

3 0

Answer:

55-15= 40

55,000-10,000=45,000

45000/55=819

i think it is 819?

Step-by-step explanation:

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The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

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3 years ago

3<br> Find the slope and y-intercept from the following graph of a linear equation.

morpeh [17]

Answer:

A. Slope = 4 and y-intercept = 3

5 0

3 years ago

Suppose you saw 300 minutes of commercials this week. How many hours of commercials did you see

lukranit [14]

1 hour = 60 minutes/300 minutes (set up a ratio problem)

5 hours

8 0

3 years ago

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Decide whether quadrilateral ABCD with vertices 4(3,1), B(-1,-1) C(1,3), and D(5.5) is a rectangle, rhombus,square, or parallelo

Sergeeva-Olga [200]

Answer: rhombus

Step-by-step explanation:

By inspection, we can tell that there are no right angles, so we can determine it is not a square or a rectangle.

From the options, it is implied that it is a parallelogram, so to determine if it is a rhombus, we can determine if there is a pair of consecutive congruent sides.

By the distance formula,

$AB=\sqrt{(-1-3)^{2}+(-1-1)^{2}}=\sqrt{16+4}=2\sqrt{5}\\BC=\sqrt{(-1-1)^{2}+(-1-3)^{2}}=\sqrt{4+16}=2\sqrt{5}$

As AB=BC, there is indeed a pair of consecutive congruent sides, and thus the most specific classification is a <em>rhombus</em>

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2 years ago

Charlie reads quickly. He reads 1\dfrac371 7 3 1, start fraction, 3, divided by, 7, end fraction pages every \dfrac23 3 2 st

OLEGan [10]

<h2>Answer:</h2>

The number of pages he will read in one minute is:

$2\dfrac{1}{7}\ \text{pages}$

<h2>Step-by-step explanation:</h2>

It is given that:

Charlie reads $1\dfrac{3}{7}\ \text{pages}$ in every $\dfrac{2}{3}\ \text{minutes}$ .

We know that:

$1\dfrac{3}{7}=\dfrac{10}{7}$

This means that:

Charlie reads $\dfrac{10}{7}\ \text{pages}$ in every $\dfrac{2}{3}\ \text{minutes}$ .

This means that:

$\text{In}\ \dfrac{2}{3}\ \text{minutes he reads}\ \dfrac{10}{7}\ \text{pages}\\\\\text{Hence}$

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{\dfrac{10}{7}}{\dfrac{2}{3}}\ \text{pages}$

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{10\times 3}{7\times 2}\ \text{pages}$

Hence,

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}$

Hence,

$\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}$

$\text{In}\ 1\ \text{minute he will read}\ 2\dfrac{1}{7}\ \text{pages}$

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3 years ago

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