<span>Northwest is 45 degrees north of west. If a car travels a distance x miles northwest, its northerly component gains x/sqrt(2) miles and its easterly component LOSES xsqrt(2)/ miles.
Resultant height is h = 4500 + 100x/sqrt(2) - 75x/sqrt(2) = [25/sqrt(2)]x + 4500
dh/dt = [25/sqrt(2)]dx/dt = [25/sqrt(2)]v </span>
Answer:


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Hope it helps...
Have a great day!!
<h3>
Answer: -13</h3>
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Explanation:
g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)
g(1) = -4 means we have the point (1,-4)
Find the slope of the line through the two points (-3,2) and (1,-4)
m = (y2-y1)/(x2-x1)
m = (-4-2)/(1-(-3))
m = (-4-2)/(1+3)
m = -6/4
m = -3/2
m = -1.5
The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5
Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation: 2 = -1.5*(-3) + b
Let's solve for b
2 = -1.5*(-3)+b
2 = 4.5 + b
2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides
-2.5 = b
b = -2.5
Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5
The last step is to plug in x = 7 and compute
g(x) = -1.5*x - 2.5
g(7) = -1.5*7 - 2.5
g(7) = -10.5 - 2.5
g(7) = -13
Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) = 

In order to maximize the revenue, set



.............(i)


.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴ 

So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94