Question

A solid cylinder with radius 0.160 m is mounted on a frictionless, stationary axle that lies along the cylinder axis. The cylinder is initially at rest. Then starting at t = 0 a constant horizontal force of 5.00 N is applied tangentially to the surface of the cylinder. You measure the angular displacement θ−θ0 of the cylinder as a function of the time t since the force was first applied. When you plot θ−θ0 (in radians) as a function of t2 (in s2), your data lie close to a straight line.
What is the moment of inertia of the wheel?

Answer 1

Answer:

we have τ = I * α as the rotational equation of motion

and we also have τ = F * r

so the torque τ = 5* 0.16 Nm = 0.8 Nm

from your plot of θ vs T^2  , calculate the slope of the line

this slope will be angular acceleration α.

Then you get I = τ/α

Explanation: