118 handle bars tells us that there's 118 bikes
if all 118 bikes were regular bikes
118*2 = 236
we would be 33 wheels short
118*1 = 118
we would be 17 seats short
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if 101 of the bikes are regular and 17 are tandem
101*1 = 101
17*2 = 34
we would have the right amount of seats
101*2 = 202
17*2 = 34
202 + 34 = 236
we would be 33 wheels short.
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if 17 bikes are tandem, 33 are tricycle, and 68 are regular
17*2 = 34
33*3 = 99
68*2 = 136
we would have the right amount of wheels
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Answer:
There are 68 bicycles, 17 tandem bicycles, and 33 tricycles.
This question isn't hard, it just takes longer since it's based off of guess and check.
Answer:
240
Step-by-step explanation:
I think hope it helps
Its just a matter of subbing...but keep in mind, for it to be a solution, it has to satisfy all 3 inequalities
x - y > = -4
2x - y < = 5
2y + x > 1
solutions are : (-1,3) and (3,5)
8,864,321
just put in order greatest to least
Answer:
b.
It's too short. Write at least 20 characters to explain it well
