Pretty sure it's the Precambrian.
        
                    
             
        
        
        
<em>m Na₂CO₃: 23g×2 + 12g + 16g×3 = 106 g/mol</em>
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1 mol ------- 106g 
X ------------ 10,6g
X = 10,6/106
<u>X = 0,1 mol Na₂CO₃</u>
        
             
        
        
        
Answer:
Explanation:
We shall apply gas law formula 
P₁ V₁ / T₁ = P₂V₂ / T₂
.914  x 350 / ( 273 + 22.7 ) = 1 x 220 / T₂
1.0818 = 220 / T₂
T₂ = 203.36 K 
= - 69.64 ⁰ C 
 
        
             
        
        
        
To find for the oxidizing agent, first let us write the
half reactions of this complete chemical reaction:
Ca = Ca2+ + 2e- <span>
2 H+ + 2e- = H2</span>
 
The oxidizing agent
would be the substance of the element that is reduced. We know that an element
is reduced when an electron is added to it. In this case, the element being
reduced is H. Therefore the oxidizing agent is HNO3.
 
Answer:
<span>HNO3</span>
 
        
                    
             
        
        
        
What are the phrases to choose from?