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3 years ago

How is energy transferred when..

Chemistry

2 answers:

IgorLugansk [536]3 years ago

7 0

Answer:

1. Each collision passes energy from particles moving quickly to particles moving slowly. In this way, the energy spreads throughout the pan and finally reaches the handle. This process is called conduction. Conduction is the transfer of heat that happens when particles collide with each other.

2. A fire spreads by transferring heat energy in three ways: Radiation, Convection, and Conduction. Radiation refers to the emission of energy in rays or waves. Heat moves through space as energy waves. ... This is the reason that when facing the fire, only the front is warmed.

3. The ways in which energy is dissipated depends on the system: ... for a tumble dryer, the electrical work is transferred into useful internal (thermal) energy which helps to dry clothes and energy is dissipated wastefully by sound waves which cause a rise in the internal energy store (temperature) of the surroundings.

Explanation:

Hope this is what you were looking for! Brainliest please?

yanalaym [24]3 years ago

6 0

Answer:

Number 1 is Conduction. Number 2 is Radiation. Number 3 is Convection. i think if thats how im supposed to word it...

Explanation:

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Explanation:

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A chemistry student needs to standardize a fresh solution of sodium hydroxide. He carefully weighs out 28.mg of oxalic acid H2C2

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Answer:

The molarity of the student's sodium hydroxide solution is 0.0219 M

Explanation:

1) Chemical reaction.

a) Kind of reaction: neutralization

b) General form: acid + base → salt + water

c) Word equation:

sodium hydroxide + oxalic acid → sodium oxalate + water

d) Chemical equation:

NaOH + H₂C₂O₄ → Na₂C₂O₄ + H₂O

b) Balanced chemical equation:

2NaOH + H₂C₂O₄ → Na₂C₂O₄ + 2H₂O

2) Mole ratio

2mol Na OH : 1 mol H₂C₂O₄ :1 mol Na₂C₂O₄ : 2 mol H₂O

3) Starting amount of oxalic acid

mass = 28 mg = 0.028 g
molar mass = 90.03 g/mol
Convert mass in grams to number of moles, n:

n = mass in grams / molar mass = 0.028 g / 90.03 g/mol = 0.000311 mol

4) Titration

Volume of base: 28.4 mL = 0.0248 liter
Concentration of base: x (unknwon)

Number of moles of acid: 2.52 mol (calculated above)

Proportion using the theoretical mole ratio (2mol Na OH : 1 mol H₂C₂O₄)

$\frac{2}{1} =\frac{x}{2.52}\\ \\ \\x=0.000311(2)=0.000622$

That means that there are 0.000622 moles of NaOH (solute)

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That is the correct number using three signficant figures, such as the starting data are reported.

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