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Nataliya [291]
2 years ago
6

How many experimental trials are needed before a hypothesis can be accepted as true ?

Chemistry
2 answers:
Lorico [155]2 years ago
6 0
Approximately, or at least the test must be repeated until 3 times, to find an accurate average and hypothesis.
Lerok [7]2 years ago
4 0
3 times or more because you need to have 3 trails or more to be able to explain why your hypothesis is correct!!
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575 394 9550<br> bFzN0S<br> come study with me!
Rina8888 [55]

Answer:

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Explanation:

7 0
2 years ago
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Calculate the mass of sodium phosphate in aqueous solution to fully react with 37 g of chromium nitrate(III) an aqueous solution
Alla [95]

Answer:

41 g

Explanation:

The equation of the reaction is;

Cr(NO3)3(aq)+Na3PO4(aq)=3NaNO3(s)+CrPO4(aq)

Number of moles of chromium nitrate = 37g/ 146.97 g/mol = 0.25 moles

1 mole of sodium phosphate reacts with 1 mole of chromium nitrate

x moles of sodium phosphate react as with 0.25 moles of chromium nitrate

x= 1 × 0.25/1

x= 0.25 moles

Mass of sodium phosphate = 0.25 moles × 163.94 g/mol

Mass of sodium phosphate = 41 g

4 0
3 years ago
The nucleus of the atom is held together by the attraction of the positively charged protons and the negatively charged electron
7nadin3 [17]
False.........................
8 0
2 years ago
What scale do we use to measure how acid or alkali something is
aniked [119]
The pH scale is used to measure how acidic or alkaline something is.

Hope that helped you!
BRAINLIEST??
4 0
2 years ago
Use the ideal gas law to calculate the concentrations of nitrogen and oxygen present in air at a pressure of 1.0 atm and a tempe
notka56 [123]

Answer:

[N₂] = 0.032 M

[O₂] = 0.0086 M

Explanation:

Ideal Gas Law → P . V = n .  R . T

We assume that the mixture of air occupies a volume of 1 L

78% N₂ → Mole fraction of N₂ = 0.78

21% O₂  → Mole fraction of O₂ = 0.21

1% another gases  → Mole fraction of another gases = 0.01

In a mixture, the total pressure of the system refers to total moles of the mixture

1 atm . 1L = n . 0.082L.atm/mol.K . 298K

n = 1 L.atm / 0.082L.atm/mol.K . 298K → 0.0409 moles

We apply the mole fraction to determine the moles

N₂ moles / Total moles = 0.78 → 0.78 . 0.0409 mol = 0.032 moles N₂

O₂ moles / Total moles = 0.21 → 0.21 . 0.0409 mol = 0.0086 moles O₂

4 0
3 years ago
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