Answer:
d + c = 122
d - 5 = 2c
so same as saying
2d + 2c = 244
we plug in for 2c
2d + d - 5 = 244
2d + d = 249
3d = 249
d = 249 / 3
d = 83
since d - 5 = 2c
83 - 5 = 2c
78 = 2c
c = 39
there are 39 cats and 83 dogs
39 + 83 = 122
Step-by-step explanation:
Remember to use PEMDAS when solving.
= 7 + (5 – 9)2 + 3(16 ÷ 8)
= 7 + (-4)2 + 3(2)
= 7 + (-8) + 6
= -1 + 6
= 5
Best of Luck!
Answer:
a. 61.92 in²
b. 21.396 ≈ 21.4%
c. $4.71
Step-by-step explanation:
a. Amount of waste = area of rectangular piece of stock - area of two identical circles cut out
Area of rectangular piece of stock = 24 in × 12 in = 288 in²
Area of the two circles = 2(πr²)
Use 3.14 as π
radius = ½*12 = 6
Area of two circles = 2(3.14*6²) = 226.08 in²
Amount of waste = 288 - 226.08 = 61.92 in²
b. % of the original stock wasted = amount of waste ÷ original stock × 100
= 61.92/288 × 100 = 6,162/288 = 21.396 ≈ 21.4%
c. 288 in² of the piece of stock costs $12.00,
Each cut-out circle of 113.04 in² (226.08/2) will cost = (12*113.04)/288
= 1,356.48/288 = $4.71.
The answer would be b - associate w it
Answer:
false
Step-by-step explanation:
the relationship between lengths/dimensions and areas is that areas are created by multiplying 2 dimensions.
when you quadruple (×4) the dimensions, then the areas are growing with the square of the factor (×4×4 = ×16), because the factor goes twice into the multiplication : one time for every dimension involved.
so, quadrupling the dimensions would multiply the areas by 16.
