PLEASE HELP (question is in picture)
1 answer:
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Answer:
Shortest distance from A to C = 102.9005 m.
Step-by-step explanation:
It is given that, ABCD is a rectangular park.
The length of the park is 80 m.
The breadth of the park is 50 m.
The diameter of the circle = 15 m.
We have to calculate the shortest distance from A to C across the park.
The distance AC = = 94.339 m.
As one has to pass only through the lines shown, he cannot pass through the circle.
So, we have to subtract the diameter of 15 m from AC
=> 94.339 m - 15 m = 79.339 m.
One must pass through either half of the circumference of the circle.
Since, diameter of circle = 15 m, its radius(r) = = 7.5 m.
The circumference of the circle = 2×π×r = 47.123 m.
Half of the circumference = = 23.5615 m.
Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.
As we have to calculate the shortest distance from A to C, one cannot pass from A to C either through B or D,
since the distance ABC or ADC = 50+80 = 130 m.
Therefore, shortest distance from A to C = 102.9005 m.
Answer:
This is the same as writing y < (-1/2)x+3
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Explanation:
The dashed boundary line goes through (0,3) and (4,1)
Apply the slope formula for those two points
m = (y2-y1)/(x2-x1)
m = (1-3)/(4-0)
m = -2/4
m = -1/2
The slope of the dashed line is -1/2. The y intercept is 3. So we go from y = mx+b to y = (-1/2)x+3 to represent the equation of the dashed line. This is the same as writing
We shade below the dashed line to represent the inequality . Points in the shaded region are solutions to the inequality. One example point is (0,0).
Note that we don't have "or equal to" as part of the inequality sign because we are not including points on the boundary. A solid line, rather than a dashed line, would include points on the boundary.