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andrew11 [14]
3 years ago
11

Raphael is traveling in a straight line at a constant speed from point A to point B. His distance from point B in miles is -20t+

45, where t is number of hours he has been traveling. What is his speed in miles per hour?
Mathematics
1 answer:
Rudik [331]3 years ago
7 0

Answer:

Speed  = 20 mi/h

Explanation:

There are two points A and B

Distance between both the points are define with function -20t + 45 miles

where t represent the number of hours of travelling.

Now firstly we find the initial position. At starting time is 0, so we put t=0 in given function of t.

At t=0;

d₀ = -20(0) + 45 = 0 + 45 = 45 miles

Now we find the distance travell after starting first hour.

Than we put t = 1 in the given function

At t = 1;

d₁ = -20(1) + 45 = -20 + 45 = 25 miles

Difference between d₁ & d₀ is

45 - 25 = 20 miles

We see that in one hour, total distace is covered 20 miles

Now we use time, speed, distance relation

Speed = distance/time

Speed= \frac{20}{1}

Speed = 20 miles/hour

That's the final answer.

I hope it will help you.

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Sliva [168]

The value of f(g(x)) is 6x^{3} +4

Explanation:

The function f(x) is given by

f(x)=2x^{2} +4

The function g(x) is given by

g(x)=\sqrt{3x^{3} }

To determine the value of f(g(x)), let us first substitute the value of g(x).

Thus, we get,

f(g(x))=f(\sqrt{3x^{3} } )

Now, substituting for x=\sqrt{3x^{3} } in the function f(x), we get,

f(g(x))=2(\sqrt{3x^{3} } )^2+4

Simplifying, the expression, we get,

f(g(x))=2({3x^{3} } )+4

Multiplying the term within the bracket, we have,

f(g(x))=6x^{3} +4

Thus, the value of f(g(x)) is 6x^{3} +4

Hence, the value of f(g(x)) represents the total amount of money that Barrett earns for working x hours.

4 0
3 years ago
Metal A has a density of 12.7 g/cm3.
stira [4]

Using the given information, the density of metal B is 8.58 g/cm³

<h3>Calculating density </h3>

From the question, we are to determine the density of metal B

From the given information,

55 g of metal A is combined with metal B to create an alloy with mass 90 g

∴ Mass of metal B in the alloy = 90 g - 55 g = 35 g

Now, we will determine the volume of metal A in the alloy

Using the formula,

Density = Mass / Volume

∴ Volume = Mass / Density

Volume of metal A in the alloy = 55/12.7

Volume of metal A in the alloy = 4.33 cm³

Then, we will determine the volume of the alloy

Volume of the alloy = 90/10.7

Volume of the alloy = 8.41 cm³

∴ Volume of metal B in the alloy = 8.41 cm³- 4.33 cm³

Volume of metal B in the alloy = 4.08 cm³

Now, for the density of metal B

Density = mass / volume

Density of metal B = 35 / 4.08

Density of metal B = 8.58 g/cm³

Hence, the density of metal B is 8.58 g/cm³.

Learn more on Calculating density here: brainly.com/question/13986137

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2 years ago
Convert 6.350 to a fraction
stepladder [879]

Answer:

6 \frac{350}{1000} Is the answer, if you want it simplified then, 6 \frac{7}{20}

Step-by-step explanation:

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Read 2 more answers
GIVEN: LJ || WK || AP, PL || AG.
galina1969 [7]

Answer:

∠1 ≅ ∠2 ⇒ proved down

Step-by-step explanation:

#12

In the given figure

∵ LJ // WK

∵ LP is a transversal

∵ ∠1 and ∠KWP are corresponding angles

∵ The corresponding angles are equal in measures

∴ m∠1 = m∠KWP

∴ ∠1 ≅ ∠KWP ⇒ (1)

∵ WK // AP

∵ WP is a transversal

∵ ∠KWP and ∠WPA are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠KWP = m∠WPA

∴ ∠KWP ≅ ∠WPA ⇒ (2)

→ From (1) and (2)

∵ ∠1 and ∠WPA are congruent to ∠KWP

∴ ∠1 and ∠WPA are congruent

∴ ∠1 ≅ ∠WPA ⇒ (3)

∵ WP // AG

∵ AP is a transversal

∵ ∠WPA and ∠2 are interior alternate angles

∵ The interior alternate angles are equal in measures

∴ m∠WPA = m∠2

∴ ∠WPA ≅ ∠2 ⇒ (4)

→ From (3) and (4)

∵ ∠1 and ∠2 are congruent to ∠WPA

∴ ∠1 and ∠2 are congruent

∴ ∠1 ≅ ∠2 ⇒ proved

8 0
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