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Olegator [25]
4 years ago
13

Find the volume of each cone.​

Mathematics
1 answer:
umka2103 [35]4 years ago
3 0

Answer: 6 cm, V=48π or V=150.8 cm³

It appears the question is asking for the radius, but below I have shown how to find the volume.

Step-by-step explanation:

The radius is half of the diameter. The diameter of the cone of 12 cm. Half of 12 is 6. Therefore, the radius is 6 cm.

The formula to find the volume of a cone is V=\pi r^2\frac{h}{3}. Now that we have the radius from above, we can use that to plug into the equation along with the given height.

V=\pi (6^2)\frac{4}{3}                    [expand the exponent]

V=36\pi \frac{4}{3}                       [combine like terms]

V=48\pi or V=150.8 cm^3            

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Sixteen students went on a week-long hiking trip. They brought with them 320 cookies. What is the ratio of cookies to students?
Yuki888 [10]
I believe that would be 320:16, but I also believe that can be reduced down to 20:1.
4 0
3 years ago
Read 2 more answers
Evaluate the expression.
koban [17]

Answer:

-5

Step-by-step explanation:

-10 - (-5) is equal to -10 + 5

-10 + 5 is equal to -5

8 0
4 years ago
An ordinary (fair) die is a cube with the numbers 1 through 6 on the sides (represented by painted spots). Imagine that such a d
anygoal [31]

Answer:

The probability of event <em>A</em> is \frac{7}{11}.

The probability of event <em>B</em> is \frac{6}{11}.

Step-by-step explanation:

The sample space of rolling a fair six-sided dice is as follows:

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

      (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

      (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

      (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

      (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

      (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

Now consider the experiment of the computing the sum of the two rolls as follows:

X = {2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

Number of total outcomes, <em>N</em> = 11.

The probability of an event <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

The event <em>A</em> is defined as the sum is greater than 5.

The sample space of <em>A</em> is:

A = {6, 7, 8, 9, 10, 11, 12}

n (A) = 7

Compute the probability of event <em>A</em> as follows:

P(A)=\frac{n(A)}{N}=\frac{7}{11}

Thus, the probability of event <em>A</em> is \frac{7}{11}.

The event <em>B</em> is defined as the sum is an even number.

The sample space of <em>B</em> is:

B = {2, 4, 6, 8, 10, 12}

n (B) = 6

Compute the probability of event <em>B</em> as follows:

P(B)=\frac{n(B)}{N}=\frac{6}{11}

Thus, the probability of event <em>B</em> is \frac{6}{11}.

7 0
3 years ago
Is 5x² a term in math​
Eduardwww [97]
Yes it is I believe
5 0
3 years ago
Read 2 more answers
Convert <br>431 base 10 divided by 112base 10 Then u should convert the final answer to base 5​
Rainbow [258]

Answer:

32115

Step-by-step explanation:

Step1

Converting 431 to base 10.

4*102=400

3*101=30

1*100=1

Adding all to get Ans=43110

Step2 converting 43110 to 5

The equation calculation formula for 43110 number to 5 is like this below.

5|431

5|86|1

5|17|1

5|3|2

5|3|3

Ans:32115

5 0
3 years ago
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