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3 years ago

Help find the volume.

Mathematics

2 answers:

Radda [10]3 years ago

8 0

C times A times A plus D times B times A=
144 Plus 180= 324

Mrac [35]3 years ago

6 0

The answer you are looking for is 324

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5. A line has a slope of (-3/2) and a y-intercept of (-4). Write the equation of the line.

KATRIN_1 [288]

Answer:

Y=-3/2x-4

Step-by-step explanation:

Point slope form is

y=mx+b

mx is the slope

and b is the y-intercept

6 0

3 years ago

P = 2L + 2W<br>How Do I Find W?

tatyana61 [14]

P = 2L + 2W ....subtract 2L from both sides
P - 2L = 2W ...divide both sides by 2
(P - 2L) / 2 = W .....can also be written like (P/2) - L = W

3 0

3 years ago

Read 2 more answers

What are the x-intercepts of the graphed function , (-3,0) and (0,1.5), (-3,0) and (1,0), (-1,2) and (1,0), (0,1.5) and (1,0)

serg [7]

Answer:

(-3,0) and (1,0)

Step-by-step explanation:

x-intercepts are the points where the y-coordinate is zero. Based on the options you have listed, they are ...

(-3,0) and (1,0)

_____

We'd need to see the graph to tell where it crosses the x-axis.

8 0

3 years ago

Colton wrote a ratio comparing the number of sports video games that he owns to the number of driving video games that he owns a

alina1380 [7]

Answer:

there are no other ratios shown but 8:6,12:9,16:12,20:15,and 24:18 are all equivalent

Step-by-step explanation:

smile time

8 0

3 years ago

If the squared difference of the zeroes of the quadratic polynomial x2+kx+30 is equal to 169 find the value of k and the zeroes

anyanavicka [17]

ANSWER

$x = 2 \: \: or \: \: x = 15$

$x = - 2 \: \: or \: \: x = - 15$

EXPLANATION

The given polynomial is

$f(x) = {x}^{2} + kx + 30$

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

$m + n = - \frac{b}{a} = -k$

and the product of roots is

$mn = \frac{c}{a} = 30$

The square difference of the zeroes is given by the expression.

$( {m - n})^{2} = {(m + n)}^{2} - 4mn$

From the question, this difference is 169.

This implies that:

$( { - k)}^{2} - 4(30) = 169$

${ k}^{2} -120= 169$

$k^{2} = 289$

$k= \pm \sqrt{289}$

$k= \pm17$

We substitute the values of k into the equation and solve for x.

$f(x) = {x}^{2} \pm17x + 30$

$f(x) = (x \pm2)(x \pm 15)$

The zeroes are given by;

$(x \pm2)(x \pm 15) = 0$

$x = \pm2 \: \: or \: \: x = \pm 15$

5 0

3 years ago