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Cerrena [4.2K]
3 years ago
10

The length of a rectangular garden is 7 feet longer than its width. If the garden’s perimeter is 178 feet what is the area of th

e garden in square feet.
Mathematics
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:1968ft^2

Step-by-step explanation:

Perimeter(p)=178feet

P=2L+2w

178=2L+2w

178=2(L+w)

L+w=178 ➗ 2

L+w=89.............(1)

W+7=L

L-w=7...................(11)

L+w=89... ..........(1)

L-w=7...................(11)

Subtract (11) from (1)

2w=89-7

2w=82

w=82 ➗ 2

w=41 width=41feet

Substitute w=41 in (11)

L-w=7

L-41=7

L=7+41

L=48feet

Area= length x width

Area=48 x 41

Area=1968ft^2

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(−4x^4 +6x^2 +3) − (5x^2 - 3)
Alborosie

Answer:

-4x^{4} + x^{2} + 6

Step-by-step explanation:

(-4x^{4} + 6x^{2} + 3) - (5x^{2} - 3) = -4x^{4} + 6x^{2} + 3 - 5x^{2} + 3 = -4x^{4} + 6x^{2} - 5x^{2} + 3 + 3 =  -4x^{4} + x^{2} + 6

7 0
3 years ago
Simplify the expression 2(4x)
fredd [130]

Answer:

Multiply 2 by the coefficient 4 and you get 8x, which is the answer

5 0
3 years ago
Read 2 more answers
A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w
melamori03 [73]

Answer:

The hypothesis is:

<em>H₀</em>: p_{X}-p_{Y}=0.

<em>Hₐ</em>: p_{X}-p_{Y}.

Step-by-step explanation:

Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.

The information provided is:

n_{X}=150\\X=88\\n_{Y}=200\\Y=130

Compute the sample proportion of men and women who exercise regularly as follows:

\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587

\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and \hat p_{X}=0.587.

The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and \hat p_{Y}=0.65.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\hat p=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e. p_{X}-p_{Y}=0.

<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e. p_{X}-p_{Y}.

6 0
3 years ago
Read 2 more answers
Can someone help me
pantera1 [17]

Step-by-step explanation:

I guess, the problem is to understand :

what means "average" ?

well, the average of a defined set of data points is the sum of the data divided by the number of data points (or samples).

that way you get a mean value for each time the system is "measured" (a data point is created).

each new measurement / data point changes the mean value (or average).

this is used all the time - in sports statistics (e.g. the average score of a team), in daily life (like the average height of a human being that defines sizes of clothes, beds, chairs, tables, even the typical height of ceilings and so on).

the average of these 8 data points is therefore :

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so, if he wants to raise his average score to 35 with the results of the next 2 games, this has 2 things to be considered :

1. the number of days points will be then 8+2=10 (and not just 8).

2. we need to add 2 data points, so that the sum of all 10 data points divided by 10 is then 35.

(36+37+34+23+47+27+31+21+x+y)/10 = 35

(36+37+34+23+47+27+31+21+x+y) = 350

x + y = 350 - 256 = 94

that means, he has to score a total of 94 points in the next 2 games.

it does not matter, how many in any single game, as long as the sum of both games is 94.

since the question is phrased "how many in each of the next 2 games", we simply take the target average of these 2 games.

remember, sum/amount = 94/2 = 47.

so, he would have to score 47 points in each of the next 2 games to raise his general average score to 35.

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Which graph ??.........

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